Sin(kx)=0=>x=0,π,...
∫0πsin(kx)dx=−1/kcos(kx)|π0=−1/k(cos(kπ)−cos(k∗0))
if k is odd then,=−1/k(−1−1)=−1/k(−2)=2/k
if k is even then,=−1/k(1−1)=0
Answer:
m=15
Step-by-step explanation:
The answer is c mean = median
x + 15 = 24
subtract 15 from both sides
x = 24 - 15 = 9
