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OLga [1]
2 years ago
14

What's the answers???? 7.6 x 2.9 = ?​

Mathematics
2 answers:
umka21 [38]2 years ago
8 0

22.04 \\  \\ hope \: it \: helps

ValentinkaMS [17]2 years ago
5 0

Answer:

22.04

Step-by-step explanation:

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In which of the following intervals does the trigonometric inequality csc(x)> -sec(x) always hold true?
Kaylis [27]
Answer:a is the answer
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3 years ago
You earn $20.00 per hour at your job. If you get a 10% raise at the end of each year, what will your hourly rate, h, be after 8
love history [14]
R is the rate (10%)
C=20, begiing rate
T=time=8

so

h=20(1+0.10)^8
h=20(1.1)^8
h=42.8718
ronnd

$42.87


D is answer

4 0
3 years ago
Find the measure of angle x in the figure below:
Crank

Answer:

70 degrees

Step-by-step explanation:

Because an area of a triangle is 180.

55 + 55 = 110    180 - 110 = 70

110 + 70 = 180

8 0
3 years ago
Read 2 more answers
Each of these extreme value problems has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to f
tino4ka555 [31]

Answer:

The minimum value of the given function is f(0) = 0

Step-by-step explanation:

Explanation:-

Extreme value :-  f(a, b) is said to be an extreme value of given function 'f' , if it is a maximum or minimum value.

i) the necessary and sufficient condition for f(x)  to have a maximum or minimum at given point.

ii)  find first derivative f^{l} (x) and equating zero

iii) solve and find 'x' values

iv) Find second derivative f^{ll}(x) >0 then find the minimum value at x=a

v) Find second derivative f^{ll}(x) then find the maximum value at x=a

Problem:-

Given function is f(x) = log ( x^2 +1)

<u>step1:</u>- find first derivative f^{l} (x) and equating zero

  f^{l}(x) = \frac{1}{x^2+1} \frac{d}{dx}(x^2+1)

f^{l}(x) = \frac{1}{x^2+1} (2x)  ……………(1)

f^{l}(x) = \frac{1}{x^2+1} (2x)=0

the point is x=0

<u>step2:-</u>

Again differentiating with respective to 'x', we get

f^{ll}(x)=\frac{x^2+1(2)-2x(2x)}{(x^2+1)^2}

on simplification , we get

f^{ll}(x) = \frac{-2x^2+2}{(x^2+1)^2}

put x= 0 we get f^{ll}(0) = \frac{2}{(1)^2}   > 0

f^{ll}(x) >0 then find the minimum value at x=0

<u>Final answer</u>:-

The minimum value of the given function is f(0) = 0

5 0
4 years ago
PLEASE I NEED HELP WITH THIS SO I CAN PASS
torisob [31]
Guess ur not passing today
5 0
3 years ago
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