I believe it might be this: 100(2 + 7)
Step-by-step explanation:
We must prove that
cos²a(csc²a-cot²a) = cos²a
If we look at both sides, we can see that we have cos²a * something = cos²a. Therefore, if we can get that something to equal 1, we have our proof. In this case, that something is csc²a-cot²a. Using this information, we can work from within the parenthesis and go from there.
We can start by expanding the items in the parenthesis. Taking that csc(x) = 1/sin(x) and cot(a) = cos(x)/sin(x), we can say that
cos²a(csc²a-cot²a) = cos²a(1/sin²a - cos²a/sin²a). Because both items in the parenthesis have a denominator of sin²a, we can subtract cos²a from 1 to get
cos²a(1/sin²a - cos²a/sin²a)= cos²a((1-cos²a)/sin²a))
Next, we know that cos²a+sin²a=1, so 1-cos²a = sin²a. Plugging that in, we get
cos²a((1-cos²a)/sin²a)) = cos²a(sin²a/sin²a)
= cos²a(1)
= cos²a
Answer:
c = 12.5
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Trigonometry</u>
[Right Triangles Only] Pythagorean Theorem: a² + b² = c²
- a is a leg
- b is another leg
- c is the hypotenuse<u>
</u>
Step-by-step explanation:
<u>Step 1: Identify</u>
Leg <em>a</em> = 7.5
Leg <em>b</em> = 10
Hypotenuse <em>c</em> = <em>c</em>
<em />
<u>Step 2: Solve for </u><em><u>c</u></em>
- Substitute in variables [Pythagorean Theorem]: 7.5² + 10² = c²
- Rewrite: c² = 7.5² + 10²
- Evaluate exponents: c² = 56.25 + 100
- Add: c² = 156.25
- [Equality Property] Square root both sides: c = 12.5
Since the programming language for this program is not specified, here's a simple JAVA program for you:
public class Card //Name of your program
{
private short rank, suit;
private static String[] suits = { "hearts", "spades", "diamonds", "clubs" };
private static String[] ranks = { "Ace", "2", "3", "4", "5", "6", "7", "8", "9", "10", "Jack", "Queen", "King" };
public static String rankAsString( int __rank ) {
return ranks[__rank];
}
Card(short suit, short rank)
{
this.rank=rank;
this.suit=suit;
}
public @Override String toString()
{
return ranks[rank] + " of " + suits[suit];
}
public short getRank()
{
return rank;
}
public short getSuit()
{
return suit;
}
}//End of program