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Marianna [84]
3 years ago
11

The square of the sum of two consecutive natural numbers is greater than the sum of the squares of these two numbers by 112. fin

d the two numbers.
Mathematics
1 answer:
Verdich [7]3 years ago
3 0
We solve the equation, ( a + a + 1 )^2 = 112 + a^2 + ( a + 1 )^2;
Then, ( 2a + 1 )^2 = 112 + a^2 + a^2 + 2a +1;
4a^2 + 4a + 1 = 113 + 2a^2 + 2a;
Finally, 2a^2 + 2a - 112 = 0;
a^2 + a - 56 = 0; 
We use <span>Quadratic Formula for this Quadratic Equation;
The solutions are a1 = 7 and a2 = -8;
But a is a natural number; so, a = 7;
The natural consecutive numbers are 7 and 8.</span>
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Solution:

We know that,

\text{Number of pages filled}=\dfrac{\text{Total cards}}{\text{Cards in each page}}

Putting the given values, we get

\text{Number of pages filled}=\dfrac{625}{9}

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3 years ago
What’s the answer to 0.462 / 0.2
Maurinko [17]

Answer:

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8 0
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OLEGan [10]

Answer:

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Step-by-step explanation:

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Given that two arcs subtend angle 125 degrees at the centre.

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5 0
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Answer:

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Step-by-step explanation:

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Angelina_Jolie [31]

Answer:

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(Multiplying each of the numbers also yields 240)

4 0
3 years ago
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