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Artyom0805 [142]
2 years ago
14

Given the function defined by g(x)=-x^2-3x+3, find g (-2). Simplify G(-2)=

Mathematics
1 answer:
Naya [18.7K]2 years ago
8 0

Answer:

put the value of x is (_2) and solve

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Two airplanes are are 1600 miles apart and heading toward each other at different altitudes. The first plane is traveling north
Elden [556K]

The planes will pass each other in 1.14 hours.

Why?

To solve the problem, we must remember that since both planes are heading toward each other, the speed to the calculations will be their combined speeds.

The speed will be:

Speed=PlaneA+PlaneB\\\\Speed=620mph+780mph=1400mph

Now, calculating the time, we have:

x=v*t\\\\1600mi=1400mph*t\\\\t=\frac{1600mi}{1400mph}=1.14hours

Hence, the planes will pass each other in 1.14 hours.

Have a nice day!

6 0
3 years ago
What is the y-intercept of the function f(x) =-2/9x + 1/3?<br> -2/9<br> -1/3<br> 1/3<br> 2/9
hoa [83]

Answer:

1/3 is the y-intercept of the function

6 0
4 years ago
Read 2 more answers
Based on the diagram, which expresses all possible
Savatey [412]

Answer: AB=85

Step-by-step explanation:

5 0
2 years ago
QUICK!
pochemuha
So,

In order to find numbers that are in between 3/8 and 6/7, Lucy must make common denominators first.

LCM of 8 and 7: 56

Multiply each fraction by the appropriate form of 1:
\frac{3}{8} *  \frac{7}{7}\ AND \  \frac{6}{7} *  \frac{8}{8}

\frac{21}{56}\ AND\  \frac{48}{56}

We can immediately see that any fraction with a numerator between 21 and 48 and a denominator of 56 will fit into the criteria Lucy needs.

The correct option is B.
4 0
4 years ago
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Assume that the Poisson distribution applies to the number of births at a particular hospital during a randomly selected day. As
kakasveta [241]

Answer:

0.9999985  = 99.99985% probability that in a day, there will be at least 1 birth.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Assume that the mean number of births per day at this hospital is 13.4224.

This means that \mu = 13.4224

Find the probability that in a day, there will be at least 1 birth.

This is:

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-13.4224}*13.4224^{0}}{(0)!} = 0.0000015

Then

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0000015 = 0.9999985&#10;

0.9999985  = 99.99985% probability that in a day, there will be at least 1 birth.

7 0
3 years ago
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