Answer: The angle equals 45
∘ and the supplement is 135
∘
Explanation:
Since the supplement is three times the angle, we can say s = 3
a
Since we know the supplement is
180
−
a
, we can plug that in.
180 - a = 3a
180 =
4
a (add a to both sides)
45 = a (divide both sides by 4)
Since we know the angle now, all we have to do is multiply it times 3 to find the supplement.
45 × 3 = 135
What is the interquartile range of the data set below? Growth in feet of oak trees: 68,80,73,90,120,94,76,112,101,94,72 (1) 22
sdas [7]
<span>68,80,73,90,120,94,76,112,101,94,72 --->
68, 72, 73, 76, 80, 90, 94, 94, 101, 112, 120
Median = 90
Lower Median = 73
Upper Median = 101
IQR = 101 - 73
IQR = 28</span>
This exponential growth/decay (in this case decay because r<1) of the form:
f=ir^t, f=final value, i=initial value, r=common ratio or "rate", t=time.
Since the population decreases by 4.5% each year the common ratio is:
r=(100-4.5)/100=0.955 so we can say
P(t)=8500(0.955^t)
....
7000=8500(0.955^t)
14/17=(955/1000)^t taking the natural log of both sides
ln(14/17)=t ln(955/1000)
t=ln(14/17)/ln(955/1000)
t≈4.22 years (to nearest hundredth of a year)
Since t is the years since 2010, the population will fall to 7000 in the year (2010+4.22=2014.22, more than four years will have elapsed) 2015.
Answer:
a) 0.264
b) 48 cubit light-years
Step-by-step explanation:
For calculating a) What is the probability of 3 or more stars in 16 cubic light years?
a)
λ= 1 star/16 cubic light-years
t= measure t in units of 16 cubic light years.
E(Y) = λ t = (1/16)(16) = 1 star
P(X>=2) = 1 - P(X<2)
= 1 - [e^-1 + (e^-1)(1)/1!]
= 0.264
b)
P(X≥1) = 1 - P(X=0)
= 1 - e^-μ
0.95 = 1 - e^-μ
e^-μ = 1 - 0.95
e^-μ = 0.05
ln(e^-μ) = ln(0.05)
-μ = -3
μ = 3
Therefore 3 x 16 = 48 cubic light years of space
Answer:
old mcdonald had a farm eee aye eee aye oooh
Step-by-step explanation:
And on that farm there was a dinosaur eee aye eee aye oooh with a RAwR RawR here and a rAWr RAWR there here a RawR there a rawR everywhere a RAwr rAWR ol mcdonald had a farm ee aye ee aye ohhhhhhhh
