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2 years ago

For most stars, what does a higher temperature tend to go with?

Biology

2 answers:

Korvikt [17]2 years ago

7 0

I think the answer is a red color

valkas [14]2 years ago

3 0

Answer:

A higher luminosity

Explanation:

Luminosity is the apparent brightness of a star. Temperature impacts the luminosity as the hotter the temperature is, the more energy/reactions there is, which results in a higher luminosity.

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Which characteristic features are common in archea and eukaryotes?

UkoKoshka [18]

Vacuoles, ribosomes, central plasmic membrane

8 0

3 years ago

Humans use many chemical substances for farming that consequently affect biodiversity. These compounds, which are rich in nitrog

posledela

Answer:

algal growth due to eutrophication

Explaination:

Eutrophication is where these nutrient rich compounds mix with nearby water sources and promote the growth of large amounts of algae. Algae go through respiration and take up the dissolved O2 in water which causes these areas to experience low O2 levels. Everything needs O2 to survive thus nearby organisms and plants die out creating dead zones.

7 0

3 years ago

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How do levels of acid rain and so2 emissions relate to each other

galben [10]

They relate because they have the same bonds

4 0

3 years ago

Most black bears (Ursus americanus) are black or brown in color. However, occasional white bears of this species appear in some

Sphinxa [80]

Answer and Explanation:

The number of observed individuals:

AA 42

AG 24

GG 21

Total number of individuals, N= 87 = 42 + 24 + 21

Allelic frequencies:

f(p) = (2 x AA + AG)/ 2 x N

f (p)= (2 x 42 + 24) /2 x 87

f (p) = (84 + 24) / 174

f (p)= 108 / 174

f (p) = 0.62

f (q) = (2 x GG + AG)/2 x N

f (q) = (2 x 21 + 24 )/2 x 87

f (q) = (42 + 24)/ 174

f (q) = 66/174

f (q) = 0.38

p + q = 1

0.62 + 0.38 = 1

The expected genotypic frequency:

F (AA)= 0.62 ² = 0.3844

F (AG) = 2 x A x G = 2 x 0.62 x 0.38 = 0.4712

F (GG) = 0.38 ² = 0.1444

AA + AG + GG = 0.3844 + 0.4712 + 0.1444 = 1

The number of expected individuals:

AA= (0.62)² x 87 = 0.3844 x 87 = 33.44

AG= (0.4712) x 87 = 40.99

GG= (0.38)² x 87 = 12.563

Total number of expected individuals = 33.44 + 40.99 + 12.563 = 87

Chi square= sum (O-E)²/E

AA= (O-E)² /E

AA=(42 - 33.44) ² / 33.44

AA= 2.2

AB= (O-E)² /E

AB= (24 - 40.99)²/ 40.99

AB=7.04

BB=(O-E)² /E

BB= (21-12.563)²/12.563

BB= 5.66

Chi square= sum ((O-E)²/E) = 2.2 + 7.04 + 5.66 = 14.9

Degrees of freedom = genotypes - alleles = 3 - 1 = 2

p value less than 0.05

There is enough evidence to reject the nule hypothesis. The genotype frequencies are not in equilibrium.

5 0

3 years ago

When there is a lack of resources such as food, water, sunlight, shelter, and space this is often called

nignag [31]

Answer:

Limiting factors

Explanation:

6 0

1 year ago

Read 2 more answers