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sp2606 [1]
2 years ago
5

Look at the picture it has the question

Mathematics
2 answers:
tester [92]2 years ago
5 0

Answer:

D

Step-by-step explanation:

3^5= 243

D) 3^8=6561

3^3=27

6561/27=243

gogolik [260]2 years ago
5 0
243 thats the answer
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Solve this problem.
Katyanochek1 [597]

Answer:

Let x = the width of the smaller rectangle.

The length of the smaller rectangle is 2x - 1.

Area is A = lw

So the area of the smaller rectangle is A = (x)(2x - 1) = 2x^2 - x

Step-by-step explanation:

hope it helped

3 0
3 years ago
Juliet needs to rewrite 3(x+2)=6y in slope intercept form so she can easily graph it which step would be correct to start the pr
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6 0
4 years ago
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A particle, initially 15 m from the origin and travelling at -2 ms), accelerates at a constant rate and ends up -20 m from the o
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the general equation for velocity in terms of acceleration and displacement is: v² = v₀² + 2ax.

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5 0
2 years ago
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6 0
3 years ago
The half life of silicone-32 is 710 years. If 30 grams is present now, how much will be present in 300 years?
Irina18 [472]

Answer:

22.38 g of silicone-32 will be present in 300 years.

Step-by-step explanation:

A radioactive half-life refers to the amount of time it takes for half of the original isotope to decay and its given by

                                           N(t)=N_0(\frac{1}{2})^{\frac{t}{t_{1/2}}

where,

N(t) = quantity of the substance remaining

N_0 = initial quantity of the substance

t = time elapsed

t_{1/2} = half life of the substance

From the information given we know:

  • The initial quantity of silicone-32 is 30 g.
  • The time elapsed is 300 years.
  • The half life of silicone-32 is 710 years.

So, to find the quantity of silicone-32 remaining we apply the above equation

N(t)=30\left(\frac{1}{2}\right)^{\frac{300}{710}}=30\left(\frac{1}{2}\right)^{\frac{30}{71}}\approx22.38 \:g

22.38 g of silicone-32 will be present in 300 years.

7 0
3 years ago
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