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2 years ago

Look at the picture it has the question

Mathematics

2 answers:

tester [92]2 years ago

5 0

Answer:

Step-by-step explanation:

3^5= 243

D) 3^8=6561

3^3=27

6561/27=243

gogolik [260]2 years ago

5 0

243 thats the answer

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What is the common difference d of the sequence nine -8 -25 -42 -59

ZanzabumX [31]

Answer:

The common difference d in the given sequence is -17

Step-by-step explanation:

We need to find the common difference d of the following sequence 9 -8 -25 -42 -59

We have a₁ = 9

and a₂ = -8

The formula used is: $a_n=a_1+(n-1)d$

By putting values we can find the value of d

We have n=2, a₂ = -8, a₁ = 9 and we need to find d

$a_n=a_1+(n-1)d\\a_2=a_1+(2-1)d\\-8=9+d\\d=-8-9\\d=-17$

So, the common difference d in the given sequence is -17

6 0

3 years ago

What is the domain of the function represented by the graph? A graph shows an upward parabola on a coordinate plane vertex at (m

vlabodo [156]

Using it's concept, the domain of the function represented by the graph is all real numbers.

<h3>What is the domain of a function?</h3>

The domain of a function is the set that contains all possible input values for the function.

In this problem, a parabola is used, which has no restriction such as an even root or a fraction, hence the domain is all real values.

More can be learned about the domain of a function at brainly.com/question/10891721

#SPJ1

3 0

2 years ago

An airplane leaves an airport and flies due west 150 miles and then 170 miles in the direction S 49.17°W. How far is the plane f

Sphinxa [80]

Answer:

Distance between plane and airport is 134.4 miles.

Step-by-step explanation:

Given : An airplane leaves an airport and flies due west 150 miles and then 170 miles in the direction S 49.17°W.

To find : How far is the plane from the airport.

Solution : Distance from airport to west is 150 miles and then 170 miles in the direction south and angle form is S 49.17° W

Refer the attached picture for clearance.

Applying law of cosines

$c^2=a^2+b^2-2ab Cos(C)$

$c=\sqrt{a^2+b^2-2ab Cos(C)}$

where a= 150 miles

b=170 miles

C= 49.17° angle in degree

c = distance between plane from the airport

Put values in the formula,

$c=\sqrt{a^2+b^2-2ab Cos(C)}$

$c=\sqrt{150^2+170^2-2(150)(170) Cos(49.17^{\circ})}$

$c=\sqrt{22500+28900-51000(0.653)}$

$c=\sqrt{51400-33303}$

$c=\sqrt{18057}$

$c=134.37$

Therefore, Distance between plane and airport is 134.4 miles.

5 0

3 years ago

Read 2 more answers

Amir can travel 121.72 miles on 6.8 gallons of gas.

ASHA 777 [7]

The unit consumption of gas can be obtained by dividing the total distance traveled in miles by the total gallons of gas consumed by the trip. This is shown below:

121.72 miles / 6.8 gallons = 17.9

Therefore, on a gallon of gas, Amir can travel 17.9 miles, which is letter B among the choices.

4 0

3 years ago

braden is hiking on a mountain. At 11:00 am he is at an elevation of 500 feet. At 2:00pm he is 900 fett. Find the rate of change

den301095 [7]

Answer:

He changed the elevation by 400 feet

7 0

2 years ago