Two supplemental angles add up to 180°
So we have (A + B = 180°)
The measure of one of them is always 180° - the other.
A = 180° - B
B = 180° - A
the cheap answer is simply
(x-5)(x²+4x-2)
we can simply multiply the terms on one by the terms of the other and then add like-terms and simplify.
![\bf (x-5)(x^2+4x-2)\implies \begin{array}{cllll} x^2+4x-2\\ \times x\\ \cline{1-1}\\ x^3+4x^2-2x \end{array}+ \begin{array}{cllll} x^2+4x-2\\ \times -5\\ \cline{1-1}\\ -5x^2-20x+10 \end{array} \\\\\\ x^3+4x^2-2x-5x^2-20x+10\implies x^3+4x^2-5x^2-2x-20x+10 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill x^3-x^2-22x+10~\hfill](https://tex.z-dn.net/?f=%5Cbf%20%28x-5%29%28x%5E2%2B4x-2%29%5Cimplies%20%5Cbegin%7Barray%7D%7Bcllll%7D%20x%5E2%2B4x-2%5C%5C%20%5Ctimes%20x%5C%5C%20%5Ccline%7B1-1%7D%5C%5C%20x%5E3%2B4x%5E2-2x%20%5Cend%7Barray%7D%2B%20%5Cbegin%7Barray%7D%7Bcllll%7D%20x%5E2%2B4x-2%5C%5C%20%5Ctimes%20-5%5C%5C%20%5Ccline%7B1-1%7D%5C%5C%20-5x%5E2-20x%2B10%20%5Cend%7Barray%7D%20%5C%5C%5C%5C%5C%5C%20x%5E3%2B4x%5E2-2x-5x%5E2-20x%2B10%5Cimplies%20x%5E3%2B4x%5E2-5x%5E2-2x-20x%2B10%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20~%5Chfill%20x%5E3-x%5E2-22x%2B10~%5Chfill)
Answer:
0
Step-by-step explanation:
Rewrite the equation as x^2-3x+9=0
find the determinant.
D = b^2-4ac = (-3)^2-4*1*9 <0
no solution
The answer is .002 after you multiply the equations inside the parentheses and divide them
It can't be graphed because it's not a proper function