Answer:
3/4
Step-by-step explanation:
Given the following :
Number of boxes = 2
First box :
White balls = 3
Blue balls = 2
Second box:
White balls = 4
Blue balls = 1
What is the probability that Frida picked a ball from the first box if she has selected a blue ball?
Probability (P) = (required outcome / Total possible outcomes)
Probability of picking first box : P(F) = 1/2
Probability of not picking second box :P(S) 1/2
Probability of picking blue from first box : P(B | F) = 3/5
Probability of picking blue, but not from first box : P(Blue not from second box) P(B|S) = 1/5
probability that Frida picked a ball from the first box if she has selected a blue ball?
P(F) * P(B|F) ÷ (P(F) * P(B|F)) + (P(S) * P(B|S))
(1/2 * 3/5) ÷ ((1/2 *3/5) + (1/2 * 1/5)
3/10 ÷ (3/10 + 1/10)
3/10 ÷ 4/10
3/10 * 10/4
= 3/4
Answer:
b+6
Step-by-step explanation:
3b-2b+6=(3-2)b+6=b+6
Answer:
60 minutes or 1 hour
Step-by-step explanation:
My picture is my worked out solution :)
Answer:
(a) we get that the fewest number of packages of cups and napkins should buy is 24.
(b) Number of sets of 3 packages of Cups and 2 packages of Napkins will be there.
Step-by-step explanation:
Given that,
Cups are sold in packages of 8.
Napkins are sold in package of 12.
To find:- (a) What is the fewest number of packages of cups and the fewest number of packages of napkins that can be purchased so there will be the same number of cups as napkins?
From the Question,
We have to least number of packages of cups and napkins So, we find the
L.C.M of the given data because it provide the least common multiple.
So, L.c.m of 8 & 12 is



Here we get that the fewest number of packages of cups and napkins should buy is 24.
(b) How many sets of cups and napkins will there be?
Again,
Number of packages of cups should buy = 
Number of packages of Napkins should buy = 
Hence
Number of sets of 3 packages of Cups and 2 packages of Napkins will be there.