Let us find the co ordinates of each vertex of the triangle .
Vertex A ( in firs second quadrant) = ( -5 ,3)
vertex B in third quadrant = ( -5, -5)
vertex C in fourth quadrant = ( 4, -2)
let us use distance formula AB^2 = ( -5 - 3)^2 + (-5 - -5 )^2 = 64 + 0
AB= 8
BC^2 = ( -2 - -5 )^2 + ( 4 - - 5)^2 = 9 + 81 = 90
BC = 9.48
AC^2 = ( -2 -3)^2 +( 4- -5)^2 = 25 + 81 = 106
AC= 10.29
Perimeter = sum of length of AB+ BC+ Ac = 8 + 10.29 + 9.48= 22.77
Answer:
First add 3 to each side
Then divide each side by 5
Step-by-step explanation:
5x - 3 = 12
First add 3 to each side
5x-3+3 = 12+3
5x = 15
Then divide each side by 5
5x/5 = 15/5
x = 3
Answer:
12
Step-by-step explanation:
we use Pythagoras law
√13^2-5^2
Answer:
y = 27°
Step-by-step explanation:
3y + 53 = 7y - 55
53 + 55 = 7y - 3y
4y = 108
y = 108 : 4
y = 27°
3(27) + 53 = 81 + 53 = 134°
