Find the value of x then classify the triangle by its angles

Please help solve this question been stuck for a while

damaskus [11]

Answer:

7.7

Step-by-step explanation:

To find the intersection points of the line and the circle we have to set up a system with their equations and solve. The system would look like this:

$\left \{ {{x=1 } \atop {x^2+y^2=16}} \right.$

To solve, substitute 1 for x in the second equation to get:

$1^2+y^2=16$

Solving, we get:

$y=\sqrt{15}, y=-\sqrt{15}$

Therefore, the two points of intersection are $(1,\sqrt{15} )$ and $(1,-\sqrt{15})$ . The distance between these two points (the length of the chord in the circle) is $2\sqrt{15}$ which is 7.745966692414... which is 7.7 rounded to the nearest tenth.

Hope this helps :)

6 0

3 years ago

Can someone help me for the answer to this question

storchak [24]

Yeah tell me the question I didn't get it very well

7 0

3 years ago

Each set of three points is collinear. Find each missing x- or y-value. Enter each answer to the nearest hundredth. (6, 10.2), (

Dima020 [189]

Considering that the points are part of the same linear function, the missing x-value is given by:

a. 1.1.

<h3>What is a linear function?</h3>

A linear function is modeled by:

y = mx + b

In which:

m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.

b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.

Given two points, the slope is given by <u>change in y divided by change in x</u>. In this problem, we are given points (6, 10.2) and (1.5, 3.45), hence the slope is:

m = (10.2 - 3.45)/(6 - 1.5) = 1.5.

Hence:

y = 1.5x + b.

When x = 6, y = 10.2, hence we use it to find b as follows:

10.2 = 1.5(6) + b

9 + b = 10.2

b = 1.2.

Hence the function is:

y = 1.5x + 1.2.

The value of x when y = 2.85 is given by:

y = 1.5x + 1.2.

2.85 = 1.5x + 1.2.