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Helga [31]
2 years ago
10

What is 6.729 x 8.3 (show ur work)

Mathematics
2 answers:
katen-ka-za [31]2 years ago
4 0

Answer:92,817,765

Step-by-step explanation:Arrange the numbers one on top of the other and line up the place values in columns. The number with the most digits is usually placed on top as the multiplicand.

Starting with the ones digit of the bottom number, the multiplier, multiply it by the last digit in the top number

Write the answer below the equals line

If that answer is greater than nine, write the ones place as the answer and carry the tens digit

Proceed right to left. Multiply the ones digit of the bottom number to the next digit to the left in the top number. If you carried a digit, add it to the result and write the answer below the equals line. If you need to carry again, do so.

When you've multiplied the ones digit by every digit in the top number, move to the tens digit in the bottom number.

Multiply as above, but this time write your answers in a new row, shifted one digit place to the left.

When you finish multiplying, draw another answer line below your last row of answer numbers.

Use long addition to add your number columns from right to left, carrying as you normally do for long addition.

Long Multiplication with Decimals

Long multiplication with decimals using the standard algorithm has a few simple additional rules to follow.

Count the total number of decimal places contained in both the multiplicand and the multiplier.

Ignore the decimals and right align the numbers one on top of the other as if they were integers

Multiply the numbers using long multiplication.

Insert a decimal point in the product so it has the same number of decimal places equal to the total from step 1.

gavmur [86]2 years ago
4 0

Answer:

Step-by-step explanation:

Line up the numbers:

\begin{matrix}\:\:&6&7&2&9\\ \times \:&\:\:&\:\:&8&3\end{matrix}

-------------------------------
\frac{\begin{matrix}\:\:&\:\:&\:\:&2&\:\:\\ \:\:&6&7&2&\textbf{9}\\ \times \:&\:\:&\:\:&8&\textbf{3}\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\:\:&7\end{matrix}}

\frac{\begin{matrix}\:\:&\:\:&\:\:&\textbf{2}&\:\:\\ \:\:&6&7&\textbf{2}&9\\ \times \:&\:\:&\:\:&8&\textbf{3}\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&8&7\end{matrix}}

\frac{\begin{matrix}\:\:&2&\:\:&2&\:\:\\ \:\:&6&\textbf{7}&2&9\\ \times \:&\:\:&\:\:&8&\textbf{3}\end{matrix}}{\begin{matrix}\:\:&\:\:&1&8&7\end{matrix}}

\frac{\begin{matrix}\:\:&2&\textbf{2}&\:\:&2&\:\:\\ \:\:&\:\:&\textbf{6}&7&2&9\\ \times \:&\:\:&\:\:&\:\:&8&\textbf{3}\end{matrix}}{\begin{matrix}\:\:&\:\:&0&1&8&7\end{matrix}}

\frac{\begin{matrix}\:\:&\:\:&\:\:&\:\:&7&\:\:\\ \:\:&\:\:&6&7&2&\textbf{9}\\ \:\:&\times \:&\:\:&\:\:&\textbf{8}&3\end{matrix}}{\begin{matrix}\:\:&2&0&1&8&7\\ \:\:&\:\:&\:\:&\:\:&2&\:\:\end{matrix}}

\frac{\begin{matrix}\:\:&\:\:&\:\:&2&\textbf{7}&\:\:\\ \:\:&\:\:&6&7&\textbf{2}&9\\ \:\:&\times \:&\:\:&\:\:&\textbf{8}&3\end{matrix}}{\begin{matrix}\:\:&2&0&1&8&7\\ \:\:&\:\:&\:\:&3&2&\:\:\end{matrix}}

\frac{\begin{matrix}\:\:&\:\:&5&\textbf{2}&7&\:\:\\ \:\:&\:\:&6&\textbf{7}&2&9\\ \:\:&\times \:&\:\:&\:\:&\textbf{8}&3\end{matrix}}{\begin{matrix}\:\:&2&0&1&8&7\\ \:\:&\:\:&8&3&2&\:\:\end{matrix}}

\frac{\begin{matrix}\:\:&5&\textbf{5}&2&7&\:\:\\ \:\:&\:\:&\textbf{6}&7&2&9\\ \times \:&\:\:&\:\:&\:\:&\textbf{8}&3\end{matrix}}{\begin{matrix}\:\:&2&0&1&8&7\\ \:\:&3&8&3&2&\:\:\end{matrix}}

\frac{\begin{matrix}\:\:&5&5&2&7&\:\:\\ \:\:&\:\:&6&7&2&9\\ \times \:&\:\:&\:\:&\:\:&8&3\end{matrix}}{\begin{matrix}\:\:&2&0&1&8&7\\ 5&3&8&3&2&\:\:\end{matrix}}

\frac{\begin{matrix}\:\:&\:\:&6&7&2&9\\ \:\:&\times \:&\:\:&\:\:&8&3\end{matrix}}{\begin{matrix}0&2&0&1&8&7\\ 5&3&8&3&2&0\end{matrix}}

=558507

Add Decimal Back:

=55.8507

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maks197457 [2]

The transformed function is y = 1/3(log(x/3 + 4)) + 1

<h3>How to transform the logarithmic function?</h3>

The parent logarithmic function is

y = log(x)

When shifted left by 4 units, we have:

y = log(x + 4)

When shifted up by 3 units, we have:

y = log(x + 4) + 3

When compressed vertically by 1/3, we have:

y = 1/3(log(x + 4) + 3)

This gives

y = 1/3(log(x + 4)) + 1

When stretched horizontally by 3, we have:

y = 1/3(log(x/3 + 4)) + 1

Hence, the transformed function is y = 1/3(log(x/3 + 4)) + 1

<h3>The transformation of function f(x)</h3>

We have:

f(x) = log[-(x – 5)] + 4

Set the radicand greater than 0

-(x - 5) > 0

Divide by -1

x - 5 < 0

Add 5 to both sides

x < 5 -- this represents the domain

A logarithmic function can output any real number.

So, the range is -\infty < f(x) < \infty

In the domain, we have:

x < 5

This means that the interval of decrease is -\infty < x < 5

Rewrite as an equation

x = 5 --- this represents the equation of asymptote

Read more about logarithmic functions at:

brainly.com/question/12708344

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6 0
1 year ago
Helllllpppp I need to find the area
Masja [62]
Divide it into two squares.
The first square is just (1)1, which equals 1 cm^2, and add that to the second square, which is just (2)2, which equals 4, so 1+4=5 cm^2.
3 0
3 years ago
What is the missing equation N÷6=8
solong [7]
48.

N/6 = 8
48/6 = 8
8 = 8
8 does indeed equal 8

Good luck! 


3 0
3 years ago
Read 2 more answers
A 5-foot tall person standing with her back to the sun casts an 12-foot long shadow. To the nearest degree, what angle does the
swat32

Answer:

  • 23°

Explanation:

<u>1) Data:</u>

a) height of the person = opposite-leg to the angle the sun makes with the ground = 5 ft

b) length of the shadow = adjacent-leg to the angle the sun makes with the ground = 12 ft

c) angle, α = ?

<u>2) Solution</u>

  • tanα = opposite-leg / adjacent-leg

  • tanα = 5 ft / 12 5t = 5/12

  • α = arctan(5/12) = 22.6°

  • 22.6° rounded to the nearest degree is 23° ← answer
5 0
3 years ago
We now want to solve for x.
mart [117]
-4x=-12

X=3
I’m pretty sure that is correct
7 0
2 years ago
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