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Helga [31]
2 years ago
10

What is 6.729 x 8.3 (show ur work)

Mathematics
2 answers:
katen-ka-za [31]2 years ago
4 0

Answer:92,817,765

Step-by-step explanation:Arrange the numbers one on top of the other and line up the place values in columns. The number with the most digits is usually placed on top as the multiplicand.

Starting with the ones digit of the bottom number, the multiplier, multiply it by the last digit in the top number

Write the answer below the equals line

If that answer is greater than nine, write the ones place as the answer and carry the tens digit

Proceed right to left. Multiply the ones digit of the bottom number to the next digit to the left in the top number. If you carried a digit, add it to the result and write the answer below the equals line. If you need to carry again, do so.

When you've multiplied the ones digit by every digit in the top number, move to the tens digit in the bottom number.

Multiply as above, but this time write your answers in a new row, shifted one digit place to the left.

When you finish multiplying, draw another answer line below your last row of answer numbers.

Use long addition to add your number columns from right to left, carrying as you normally do for long addition.

Long Multiplication with Decimals

Long multiplication with decimals using the standard algorithm has a few simple additional rules to follow.

Count the total number of decimal places contained in both the multiplicand and the multiplier.

Ignore the decimals and right align the numbers one on top of the other as if they were integers

Multiply the numbers using long multiplication.

Insert a decimal point in the product so it has the same number of decimal places equal to the total from step 1.

gavmur [86]2 years ago
4 0

Answer:

Step-by-step explanation:

Line up the numbers:

\begin{matrix}\:\:&6&7&2&9\\ \times \:&\:\:&\:\:&8&3\end{matrix}

-------------------------------
\frac{\begin{matrix}\:\:&\:\:&\:\:&2&\:\:\\ \:\:&6&7&2&\textbf{9}\\ \times \:&\:\:&\:\:&8&\textbf{3}\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\:\:&7\end{matrix}}

\frac{\begin{matrix}\:\:&\:\:&\:\:&\textbf{2}&\:\:\\ \:\:&6&7&\textbf{2}&9\\ \times \:&\:\:&\:\:&8&\textbf{3}\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&8&7\end{matrix}}

\frac{\begin{matrix}\:\:&2&\:\:&2&\:\:\\ \:\:&6&\textbf{7}&2&9\\ \times \:&\:\:&\:\:&8&\textbf{3}\end{matrix}}{\begin{matrix}\:\:&\:\:&1&8&7\end{matrix}}

\frac{\begin{matrix}\:\:&2&\textbf{2}&\:\:&2&\:\:\\ \:\:&\:\:&\textbf{6}&7&2&9\\ \times \:&\:\:&\:\:&\:\:&8&\textbf{3}\end{matrix}}{\begin{matrix}\:\:&\:\:&0&1&8&7\end{matrix}}

\frac{\begin{matrix}\:\:&\:\:&\:\:&\:\:&7&\:\:\\ \:\:&\:\:&6&7&2&\textbf{9}\\ \:\:&\times \:&\:\:&\:\:&\textbf{8}&3\end{matrix}}{\begin{matrix}\:\:&2&0&1&8&7\\ \:\:&\:\:&\:\:&\:\:&2&\:\:\end{matrix}}

\frac{\begin{matrix}\:\:&\:\:&\:\:&2&\textbf{7}&\:\:\\ \:\:&\:\:&6&7&\textbf{2}&9\\ \:\:&\times \:&\:\:&\:\:&\textbf{8}&3\end{matrix}}{\begin{matrix}\:\:&2&0&1&8&7\\ \:\:&\:\:&\:\:&3&2&\:\:\end{matrix}}

\frac{\begin{matrix}\:\:&\:\:&5&\textbf{2}&7&\:\:\\ \:\:&\:\:&6&\textbf{7}&2&9\\ \:\:&\times \:&\:\:&\:\:&\textbf{8}&3\end{matrix}}{\begin{matrix}\:\:&2&0&1&8&7\\ \:\:&\:\:&8&3&2&\:\:\end{matrix}}

\frac{\begin{matrix}\:\:&5&\textbf{5}&2&7&\:\:\\ \:\:&\:\:&\textbf{6}&7&2&9\\ \times \:&\:\:&\:\:&\:\:&\textbf{8}&3\end{matrix}}{\begin{matrix}\:\:&2&0&1&8&7\\ \:\:&3&8&3&2&\:\:\end{matrix}}

\frac{\begin{matrix}\:\:&5&5&2&7&\:\:\\ \:\:&\:\:&6&7&2&9\\ \times \:&\:\:&\:\:&\:\:&8&3\end{matrix}}{\begin{matrix}\:\:&2&0&1&8&7\\ 5&3&8&3&2&\:\:\end{matrix}}

\frac{\begin{matrix}\:\:&\:\:&6&7&2&9\\ \:\:&\times \:&\:\:&\:\:&8&3\end{matrix}}{\begin{matrix}0&2&0&1&8&7\\ 5&3&8&3&2&0\end{matrix}}

=558507

Add Decimal Back:

=55.8507

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Option C is correct because it is a trinomial with a leading coefficient of 3 and a constant term of -5

Step-by-step explanation:

We need to pick the expression that matches this description:

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First lets explain the terms:

Trinomial: a polynomial having 3 terms

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Constant term: Having no variable and value cannot be changed.

Now using these definitions, we can choose the correct option

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