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Helga [31]
2 years ago
10

What is 6.729 x 8.3 (show ur work)

Mathematics
2 answers:
katen-ka-za [31]2 years ago
4 0

Answer:92,817,765

Step-by-step explanation:Arrange the numbers one on top of the other and line up the place values in columns. The number with the most digits is usually placed on top as the multiplicand.

Starting with the ones digit of the bottom number, the multiplier, multiply it by the last digit in the top number

Write the answer below the equals line

If that answer is greater than nine, write the ones place as the answer and carry the tens digit

Proceed right to left. Multiply the ones digit of the bottom number to the next digit to the left in the top number. If you carried a digit, add it to the result and write the answer below the equals line. If you need to carry again, do so.

When you've multiplied the ones digit by every digit in the top number, move to the tens digit in the bottom number.

Multiply as above, but this time write your answers in a new row, shifted one digit place to the left.

When you finish multiplying, draw another answer line below your last row of answer numbers.

Use long addition to add your number columns from right to left, carrying as you normally do for long addition.

Long Multiplication with Decimals

Long multiplication with decimals using the standard algorithm has a few simple additional rules to follow.

Count the total number of decimal places contained in both the multiplicand and the multiplier.

Ignore the decimals and right align the numbers one on top of the other as if they were integers

Multiply the numbers using long multiplication.

Insert a decimal point in the product so it has the same number of decimal places equal to the total from step 1.

gavmur [86]2 years ago
4 0

Answer:

Step-by-step explanation:

Line up the numbers:

\begin{matrix}\:\:&6&7&2&9\\ \times \:&\:\:&\:\:&8&3\end{matrix}

-------------------------------
\frac{\begin{matrix}\:\:&\:\:&\:\:&2&\:\:\\ \:\:&6&7&2&\textbf{9}\\ \times \:&\:\:&\:\:&8&\textbf{3}\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\:\:&7\end{matrix}}

\frac{\begin{matrix}\:\:&\:\:&\:\:&\textbf{2}&\:\:\\ \:\:&6&7&\textbf{2}&9\\ \times \:&\:\:&\:\:&8&\textbf{3}\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&8&7\end{matrix}}

\frac{\begin{matrix}\:\:&2&\:\:&2&\:\:\\ \:\:&6&\textbf{7}&2&9\\ \times \:&\:\:&\:\:&8&\textbf{3}\end{matrix}}{\begin{matrix}\:\:&\:\:&1&8&7\end{matrix}}

\frac{\begin{matrix}\:\:&2&\textbf{2}&\:\:&2&\:\:\\ \:\:&\:\:&\textbf{6}&7&2&9\\ \times \:&\:\:&\:\:&\:\:&8&\textbf{3}\end{matrix}}{\begin{matrix}\:\:&\:\:&0&1&8&7\end{matrix}}

\frac{\begin{matrix}\:\:&\:\:&\:\:&\:\:&7&\:\:\\ \:\:&\:\:&6&7&2&\textbf{9}\\ \:\:&\times \:&\:\:&\:\:&\textbf{8}&3\end{matrix}}{\begin{matrix}\:\:&2&0&1&8&7\\ \:\:&\:\:&\:\:&\:\:&2&\:\:\end{matrix}}

\frac{\begin{matrix}\:\:&\:\:&\:\:&2&\textbf{7}&\:\:\\ \:\:&\:\:&6&7&\textbf{2}&9\\ \:\:&\times \:&\:\:&\:\:&\textbf{8}&3\end{matrix}}{\begin{matrix}\:\:&2&0&1&8&7\\ \:\:&\:\:&\:\:&3&2&\:\:\end{matrix}}

\frac{\begin{matrix}\:\:&\:\:&5&\textbf{2}&7&\:\:\\ \:\:&\:\:&6&\textbf{7}&2&9\\ \:\:&\times \:&\:\:&\:\:&\textbf{8}&3\end{matrix}}{\begin{matrix}\:\:&2&0&1&8&7\\ \:\:&\:\:&8&3&2&\:\:\end{matrix}}

\frac{\begin{matrix}\:\:&5&\textbf{5}&2&7&\:\:\\ \:\:&\:\:&\textbf{6}&7&2&9\\ \times \:&\:\:&\:\:&\:\:&\textbf{8}&3\end{matrix}}{\begin{matrix}\:\:&2&0&1&8&7\\ \:\:&3&8&3&2&\:\:\end{matrix}}

\frac{\begin{matrix}\:\:&5&5&2&7&\:\:\\ \:\:&\:\:&6&7&2&9\\ \times \:&\:\:&\:\:&\:\:&8&3\end{matrix}}{\begin{matrix}\:\:&2&0&1&8&7\\ 5&3&8&3&2&\:\:\end{matrix}}

\frac{\begin{matrix}\:\:&\:\:&6&7&2&9\\ \:\:&\times \:&\:\:&\:\:&8&3\end{matrix}}{\begin{matrix}0&2&0&1&8&7\\ 5&3&8&3&2&0\end{matrix}}

=558507

Add Decimal Back:

=55.8507

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Answer:

The amount of money in Enid bank account can be written as a linear equation.

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Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

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Where \mu=62 and \sigma=7

We are interested on this probability  on the probability that Fred will not score between 47 and 77. So we can begin finding this probability

P(47

And the best way to solve this problem is using the normal standard distribution and the z score given by:

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If we apply this formula to our probability we got this:

P(47

And we can find this probability on this way:

P(-2.143

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.  

P(-2.143

And then the probability that Fred will not score between 47 and 77 is

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Part b

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And we can find this probability on this way:

P(-2.429

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.  

P(-2.429

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