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PIT_PIT [208]
3 years ago
7

TRUE OR FALSE??

Mathematics
1 answer:
nordsb [41]3 years ago
3 0

Answer:

Step-by-step explanation:

A. True. Vertical angles have equal measure.

B. False. 12x-18=8x+10 -> x=7 -> the angles measure 66 degrees.

C. True. They're formed by a pair of intersecting lines.

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Six times the sum of three consecutive odd integers is -18 find integers
Olenka [21]

Answer:

-3, -1, 1

Step-by-step explanation:

-18 divided by 6 is -3

now guess and check the 3 consecutive odd numbers that work

6 0
3 years ago
Read 2 more answers
Find the area between the graph of the given function and the x-axis over the given interval, if possible.
icang [17]

Answer:

Not possible to find out area

Step-by-step explanation:

Given is an exponential function as

f(x) =e^{-x} and we have to find the area to the left of e above x axis under the curve.

Using integrals, we find area =

\int\limits^e_{-\infty}  e^{-x}  \, dx\\=-e^{-x}

substitute limits

When we substitute -infinity we get e^infty which is again infinity

Hence finding out area is not possible.

The integral of area diverges.

7 0
4 years ago
S is in between T and U. ST = x + 4 and SU = 2x. TU = 16. Find the value of x.
solniwko [45]
You know the total length ST and SU, so to find x you would write an equation. This would be: x+4+2x=16 Combine like terms: 3x+4=16 Subtract four from both sides: 3x=12 Divide both sides by three: x=4
8 0
3 years ago
Determine which postulate or theorem can be used to prove that
EleoNora [17]

Answer:

\triangle ABC \cong \triangle DCB by <u>AAS</u>

Step-by-step explanation:

According to the following two triangles, \triangle ABC and \triangle DCB are congruent by <u>Angle-Angle-Side</u> (AAS), because there are two angles shown and share a side, which is in the middle between triangles.

7 0
4 years ago
Linda West, a dental lab technician, pays three times as much
Natalka [10]

9514 1404 393

Answer:

  • vision: $13.50
  • dental: $40.50
  • health: $162.00

Step-by-step explanation:

Let d, v, h represent the costs of dental, vision, and health insurance, respectively. The cost relations are ...

  d = 3v . . . . . . . . . . . . . . . dental is 3 times vision

  h = 3(v +d) . . . . . . . . . . . health is 3 times vision and dental combined

  d + v + h = 9360 . . . . . annual premium

Substituting for h, we have ...

  d + v + (3(d +v)) = 9360

Substituting for d, we have ...

  3v +v +3(3v +v) = 9360

  16v = 9360

  v = 585

  d = 3v = 1755

  h = 3(d+v) = 7020

These are the total annual premiums. Linda pays 1/26 of 60% of this every two weeks. That fraction is 0.60/26 = 3/130.

a) Linda's biweekly vision insurance deduction is (585)(3/130) = $13.50

b) Linda's biweekly dental insurance deduction is (1755)(3/130) = $40.50

c) Linda's biweekly health insurance deduction is (7020)(3/130) = $162.00

_____

<em>Additional comment</em>

We know dental is 3v and health is 3(3v+v) = 12v = 4d. That is, once we find Linda's share of the biweekly vision premium, we can find the others by multiplying it by a suitable factor.

6 0
3 years ago
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