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4 years ago

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a baker has 27 wheat bagels and 36 plain bagels that will be divided into boxes. Each box must have the same number of wheat bag

els and the same number of plain bagels. What is the greatest number of boxs the baker can make using all of the bagels?

1 answer:

Damm [24]4 years ago

8 0

You need to find the Greatest Common Divisor.(GCD) or also called Greatest Common Factor.

Factors of 27 = 1, 3, 9, 27

Factors of 36 = 1, 2, 3, 4, 6, 9, 12, 18, 36
Above we can see that 9 is the greatest number each has in common so

The GCD = 9

So the greatest number of boxes the baker can make using all of the bagels is 9

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3 years ago

Equation of the line passing through (7,5) and (1, 2)

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Answer:

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2 years ago

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3 years ago

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3 years ago

Read 2 more answers

Compound interest In Exercise,$3000 is invested in an account at interest rate r,compounded continuously.Find the time required

xenn [34]

Answer:

(a) 8.15

(b) 12.92

Step-by-step explanation:

Given: P = $3000, r = 0.085

$A = Pe^{rt}$

Where

A is the Amount

P is the Principal

r is the rate

t is the time

(a) For the amount to double, A = 2 × P

A = 2 × $3000

A = $6000

$6000 = 3000e^{0.085t}$

$\frac{6000}{3000} = e^{0.085t}$

$2 = e^{0.085t}$

Take $log_{e}$ of both sides

$log_{e}2 = log_{e}e^{0.085t}$

But $log_{e}e = 1$

∴ $ln2 = 0.085t$

$t = \frac{ln2}{0.085}$

$t = \frac{0.693}{0.085}$

t = 8.15

(b) For the amount to double, A = 3 × P

A = 3 × $3000

A = $9000

$9000 = 3000e^{0.085t}$

$\frac{9000}{3000} = e^{0.085t}$

$3 = e^{0.085t}$

Take $log_{e}$ of both sides

$log_{e}3 = log_{e}e^{0.085t}$

But $log_{e}e = 1$

∴ $ln3 = 0.085t$

$t = \frac{ln3}{0.085}$

$t = \frac{1.0986}{0.085}$

t = 12.92

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3 years ago