The answer is -4 because -4^7=-16384
Answer:
Probability that the sample variance exceeds 3.10 is less than 0.05%.
Step-by-step explanation:
We are given that a process produces batches of a chemical whose impurity concentrations follow a normal distribution with a variance of 1.75.
Also, a random sample of 20 of these batches is chosen.
The probability distribution that we will used here is of Chi-square distribution, i.e.;
~
where, = sample variance
= population variance = 1.75
n = sample of batches = 20
So, probability that the sample variance exceeds 3.10 is given by = P( > 3.10)
P( > 3.10) = P( > )
= P( > 59.62) = P( > 59.62) = Less than 0.05%
From chi-square table we can observe that Probability that is greater than is less than 0.05%.
So, the probability that the sample variance exceeds 3.10 is less than 0.05%.
Step-by-step explanation:
if I understand correctly, then he bought a CD with a balance of c and an annual interest rate of 6%.
now, after this one year the CD is worth (the account balance is) c + 6% = 100% + 6% = 106% = 1.06×c
Since a and b have opposite signs then both the product and quotient will be negative. The absolute value of a · b will be greater than the absolute value of .
Without the absolute value sign, then since both the product and the quotient are negative, a · b <
Answer: the product is less than the quotient