Who does 6(5+3) equal?

1 answer:

7 0

Answer: 48
explanation: you have to do what’s in the parentheses first (5+3) that’s 8. so then you have 6(8) and 6 times 8 equals 48

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suppose the tank shown has a length of 2 feet, a width of 1 foot, and is filled with water to a depth of 8 inches. a stone is pl

nikdorinn [45]

Answer: The volume of the stone is 576 cubic inches

Step-by-step explanation: The dimensions of the tank are given in feet and inches, hence we shall use the lower of the unit of measurement that is, inches. Note that 1 foot equals 12 inches, so the length is 2 feet times 12, which equals 24 inches. Also the width is 1 foot times 12 which equals 12 inches. Then the tank is filled with water up to a depth of 8 inches , so the volume of water in the tank can be calculated as follows;

Volume = L x B x H

Where Length = 24, Width = 12 and Height = 8

Volume = 24 x 12 x 8

Volume = 2304

At 2304 cubic inches, a stone is placed in the water tank and the water level rises by 2 inches which implies that the depth is now 10 inches. With the addition of the stone, the dimensions are now shown as;

Length = 24, Width = 12, and Height = 10

Volume = L x W x H

Volume = 24 x 12 x 10

Volume = 2880

With the rise in volume of water in the tank, the difference (which is the volume of the stone) now is Volume with stone minus volume without stone, that is

Volume of stone = 2880 - 2304

Volume of stone = 576

Therefore the volume of the stone is 576 cubic inches

6 0

3 years ago

The sum of four siblings ages is 71. The second child’s age is twice the youngest, the third child’s age is twelve more than the

user100 [1]

Answer: 9, 18, 21, and 23 respectively

Step-by-step explanation:

To solve any problem like this, you want to assign a variable to each child because you dont know their age. So lets write an equation and assign variables to these children.

r = first child (youngest)

x = second child

y = third child

z = fourth child (oldest)

We know that r + x + y + z = 71

We also are given info on the comparisons of their ages.

r = r

x = 2r (2 times the youngest)

y = 12 + r (12 more than the youngest)

z = 3r - 4 (4 less than 3 times the youngest)

That was the easy part tbh, now we have to solve for 'r'. We can see that all the ages are a function of the same variable (r), and we know the sum of them is equal to 71. So lets solve for r and then plug that r value into each equation we just derived.

Child #1 (youngest)

$r+2r+(12+r)+(3r-4)=71\\3r+12+r+3r-4=71\\7r+12-4=71\\7r+8=71\\7r=63\\r=9yrs$