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3 years ago

Evaluate this surd √50+√18-√98

Mathematics

1 answer:

Dmitry [639]3 years ago

4 0

.......the answer is 7.26

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Help me, please this isn't really so hard, but I really need help

Oxana [17]

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2 years ago

Help me plz ok thank you

Gwar [14]

Answer:

If there is no 48 divided by 8 then it is 8 x _ = 48.

Step-by-step explanation:

Think about it. There are 6 times more children than adults *6 x 8 = 48.

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3 years ago

Read 2 more answers

What is the value of x to the nearest tenth

artcher [175]

The answer for your problem is x = 26

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3 years ago

Which expression is equivalent to (16 x Superscript 8 Baseline y Superscript negative 12 Baseline) Superscript one-half?.

loris [4]

To solve the problem we must know the Basic Rules of Exponentiation.

<h2>Basic Rules of Exponentiation</h2>

$x^ax^b = x^{(a+b)}$
$\dfrac{x^a}{x^b} = x^{(a-b)}$
$(a^a)^b =x^{(a\times b)}$
$(xy)^a = x^ay^a$

$x^{\frac{3}{4}} = \sqrt[4]{x^3}= (\sqrt[3]{x})^4$

The solution of the expression is $\dfrac{4x^4}{y^6}$ .

<h2>Explanation</h2>

Given to us

$(16x^8y^{12})^{\frac{1}{2}}$

Solution

We know that 16 can be reduced to $2^4$ ,

$=(2^4x^8y^{12})^{\frac{1}{2}}$

Using identity $(xy)^a = x^ay^a$ ,

$=(2^4)^{\frac{1}{2}}(x^8)^{\frac{1}{2}}(y^{12})^{\frac{1}{2}}$

Using identity $(a^a)^b =x^{(a\times b)}$ ,

$=(2^{4\times \frac{1}{2}})\ (x^{8\times\frac{1}{2}})\ (y^{12\times{\frac{1}{2}}})$

Solving further

$=2^2x^4y^{-6}$

Using identity $\dfrac{x^a}{x^b} = x^{(a-b)}$ ,

$=\dfrac{2^2x^4}{y^6}$

$=\dfrac{4x^4}{y^6}$

Hence, the solution of the expression is $\dfrac{4x^4}{y^6}$ .

Learn more about Exponentiation:

brainly.com/question/2193820

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2 years ago

In the equation x^2+10x+24=(x+a)(x+b), b is an integer. Find algebraically all possible values of b

Vinil7 [7]

(x+4)(x+6)
(x+6)(x+4)

8 0

3 years ago

Evaluate this surd √50+√18-√98​

Evaluate this surd √50+√18-√98