Answer:
i saed to answer it and it didnt show me the image so im conf
Step-by-step explanation:
so probably they are, unlees one is acxute and the other is obtuse then.... ur on ur own buddy,
Answer:
2/3 >=x
Step-by-step explanation:
8 =< -3x + 10
subtract 10 from each side
8-10 <= -3x+10-10
-2 <=-3x
divide by -3 (remember to flip the inequality)
-2/-3 >= -3x/-3
2/3 >=x
Answer: 208.
Step-by-step explanation:
The formula to find the minimum sample size is given by :-
(1)
, where z* = critical z-value (two tailed).
= Standard deviation ( from prior study ) and E = Margin of error.
As per given , we have
Margin of error : E= 0.29
Confidence level = 85%
Significance level =![\alpha=1-0.85=0.15](https://tex.z-dn.net/?f=%5Calpha%3D1-0.85%3D0.15)
Using z-table , the critical value (two -tailed)=![z^*=z_{\alpha/2}=z_{0.15/2}=z_{0.075}=1.439](https://tex.z-dn.net/?f=z%5E%2A%3Dz_%7B%5Calpha%2F2%7D%3Dz_%7B0.15%2F2%7D%3Dz_%7B0.075%7D%3D1.439)
As per previous study , Variance =![\sigma^2=8.41](https://tex.z-dn.net/?f=%5Csigma%5E2%3D8.41)
![\sigma=\sqrt{8.41}=2.9](https://tex.z-dn.net/?f=%5Csigma%3D%5Csqrt%7B8.41%7D%3D2.9)
Now, the required minimum sample size =
[Substitute the values in formula (1)]
![n=(14.39)^2](https://tex.z-dn.net/?f=n%3D%2814.39%29%5E2)
[ Round to the next integer]
Hence, the minimum number of third graders that must be included in a sample = 208.
Answer:
biotbhuvb2tupbpu2
Step-by-step explanation:
Answer:
3.84% probability that it has a low birth weight
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
![\mu = 3466, \sigma = 546](https://tex.z-dn.net/?f=%5Cmu%20%3D%203466%2C%20%5Csigma%20%3D%20546)
If we randomly select a baby, what is the probability that it has a low birth weight?
This is the pvalue of Z when X = 2500. So
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{2500 - 3466}{546}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B2500%20-%203466%7D%7B546%7D)
![Z = -1.77](https://tex.z-dn.net/?f=Z%20%3D%20-1.77)
has a pvalue of 0.0384
3.84% probability that it has a low birth weight