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slava [35]
3 years ago
5

Plzzzz help!!! quick one ​

Mathematics
1 answer:
ludmilkaskok [199]3 years ago
5 0
D= 65 degrees.

Because straight line adds up to 180
So 180-115= 65
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8h+(-6.3d)-15+4d-3.3h
Drupady [299]

Answer:

Not exactly sure if you are asking to simplify, but that is all I can do with the information you have given.

Here is the simplified version:

−2.3d + 4.7h − 15

Step-by-step explanation:

Combine Like Terms:

=8h+−6.3d+−15+4d+−3.3h

= (−6.3d+4d) + (8h+−3.3h) + (−15)

= −2.3d+ 4.7h − 15

8 0
2 years ago
Read 2 more answers
36 students for 3 teachers =<br> 1.0<br> 5<br> 12 students for 1 teacher.
11111nata11111 [884]

Answer:

12

Step-by-step explanation:

36 divided by 3 =12 for 1 teacher

6 0
2 years ago
What is 2+3x4 i already know
babymother [125]
14 is your answer bukaroo
8 0
3 years ago
100 POINTS!!Help me organize this!!!
vova2212 [387]

Step-by-step explanation:

  • 7x + 3x - 18 = 6(x + 3) === Given
  • 10x - 18 = 6(x + 3) === Combine Like Terms === 7x + 3
  • 10x - 18 = 6x + 18 ===  Distributive Property === 6(x + 3)
  • 10x - 18 - 6x = 18 === Subtraction Property of Equality === -6x both sides
  • 4x - 18 = 18 === Combine Like Terms === 10x - 6x
  • 4x = 18 + 18 === Addition Property of Equality === +18 both sides
  • 4x = 36 === Combine Like terms === 18 + 18
  • x = 36 / 4 === Division Property of Equality === /4 both sides
  • x = 9 === combine like terms??

That doesn't use the multiplication property but that's all of the rest of them.

4 0
3 years ago
a rectangle has a width that is 7 centimeters less than its length, and it’s area is 330 square centimeters. what are the dimens
WINSTONCH [101]

Answer:

The dimensions of the rectangle are 22cm of length and 15cm of width

Step-by-step explanation:

To solve this we first have to know the formula to calculate the area of ​​a rectangle

a = area = 330 cm²

L = length  =

w = width = L - 7cm

a = l * w

we replace with the known values

330 cm² = L * (l - 7cm)

330 cm² = L² - 7Lcm

0 = L² - 7Lcm - 330 cm²

when we have an equation like this we can use bhaskara

a = 1

b = -7Lcm

c = -330cm²

ax² + bx + c = 0

x = -b(±)√(b² - 4ac)/2a

we replace with the known values

L = -(-7cm)(±)√(7² - 4(1)(-330cm²)) / 2(1)

L = 7cm(±)√(49 + 1320cm²)) / 2

L = 7cm(±)√(1369cm²)) / 2

L1 = (7cm + 37cm) / 2

L1 = 44cm / 2 = 22cm

L2 = (7cm - 37cm) / 2

L2 = -30cm / 2 = -15cm

The positive represents the unknown with which we work (L) and the negative with which we do not work (W)

The dimensions of the rectangle are 22cm of length and 15cm of width

6 0
3 years ago
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