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2 years ago

Plzzzz help!!! quick one

Mathematics

1 answer:

ludmilkaskok [199]2 years ago

5 0

D= 65 degrees.

Because straight line adds up to 180
So 180-115= 65

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Y + 1 1/6 = 7 5/6 what is Y

AfilCa [17]

Answer:

6 $\frac{2}{3}$

Step-by-step explanation:

y + 1 $\frac{1}{6}$ = 7 $\frac{5}{6}$

y + $\frac{7}{6}$ = $\frac{47}{6}$

y = 40/6 = 20/3 = 6 $\frac{2}{3}$

3 0

3 years ago

PLS ANSWER ASAP 30 POINTS!!! CHECK PHOTO! WILL MARK BRAINLIEST TO WHO ANSWERS

Sveta_85 [38]

I'll do Problem 8 to get you started

a = 4 and c = 7 are the two given sides

Use these values in the pythagorean theorem to find side b

$a^2 + b^2 = c^2\\\\4^2 + b^2 = 7^2\\\\16 + b^2 = 49\\\\b^2 = 49 - 16\\\\b^2 = 33\\\\b = \sqrt{33}\\\\$

With respect to reference angle A, we have:

opposite side = a = 4
adjacent side = b = $\sqrt{33}$
hypotenuse = c = 7

Now let's compute the 6 trig ratios for the angle A.

We'll start with the sine ratio which is opposite over hypotenuse.

$\sin(\text{angle}) = \frac{\text{opposite}}{\text{hypotenuse}}\\\\\sin(A) = \frac{a}{c}\\\\\sin(A) = \frac{4}{7}\\\\$

Then cosine which is adjacent over hypotenuse

$\cos(\text{angle}) = \frac{\text{adjacent}}{\text{hypotenuse}}\\\\\cos(A) = \frac{b}{c}\\\\\cos(A) = \frac{\sqrt{33}}{7}\\\\$

Tangent is the ratio of opposite over adjacent

$\tan(\text{angle}) = \frac{\text{opposite}}{\text{adjacent}}\\\\\tan(A) = \frac{a}{b}\\\\\tan(A) = \frac{4}{\sqrt{33}}\\\\\tan(A) = \frac{4\sqrt{33}}{\sqrt{33}*\sqrt{33}}\\\\\tan(A) = \frac{4\sqrt{33}}{(\sqrt{33})^2}\\\\\tan(A) = \frac{4\sqrt{33}}{33}\\\\$

Rationalizing the denominator may be optional, so I would ask your teacher for clarification.

So far we've taken care of 3 trig functions. The remaining 3 are reciprocals of the ones mentioned so far.

cosecant, abbreviated as csc, is the reciprocal of sine
secant, abbreviated as sec, is the reciprocal of cosine
cotangent, abbreviated as cot, is the reciprocal of tangent

So we'll flip the fraction of each like so:

$\csc(\text{angle}) = \frac{\text{hypotenuse}}{\text{opposite}} \ \text{ ... reciprocal of sine}\\\\\csc(A) = \frac{c}{a}\\\\\csc(A) = \frac{7}{4}\\\\\sec(\text{angle}) = \frac{\text{hypotenuse}}{\text{adjacent}} \ \text{ ... reciprocal of cosine}\\\\\sec(A) = \frac{c}{b}\\\\\sec(A) = \frac{7}{\sqrt{33}} = \frac{7\sqrt{33}}{33}\\\\\cot(\text{angle}) = \frac{\text{adjacent}}{\text{opposite}} \ \text{ ... reciprocal of tangent}\\\\\cot(A) = \frac{b}{a}\\\\\cot(A) = \frac{\sqrt{33}}{4}\\\\$

------------------------------------------------------

Summary:

The missing side is $b = \sqrt{33}$

The 6 trig functions have these results

$\sin(A) = \frac{4}{7}\\\\\cos(A) = \frac{\sqrt{33}}{7}\\\\\tan(A) = \frac{4}{\sqrt{33}} = \frac{4\sqrt{33}}{33}\\\\\csc(A) = \frac{7}{4}\\\\\sec(A) = \frac{7}{\sqrt{33}} = \frac{7\sqrt{33}}{33}\\\\\cot(A) = \frac{\sqrt{33}}{4}\\\\$

Rationalizing the denominator may be optional, but I would ask your teacher to be sure.

7 0

1 year ago

What's the answer to 4{-4(3-12)-17}?

alexandr1967 [171]

Answer:

Step-by-step explanation:

4(-4(-9)-17)

4(36-17)

4(19)

6 0

2 years ago

Read 2 more answers

Which expression is a sum of a number and product. Answers. .8+3x .X+1 over 5 2(x-9). 5+x-4

Nookie1986 [14]

Answer:

8 + 3x

Step-by-step explanation:

A product is a multiplication, such as 3 * 5, 2x, 4y.

3x is a product.

8 + 3x is the sum of the number 8 and the product 3x.

Answer: 8 + 3x

4 0

3 years ago

Mike’s room is 12 feet by 16 feet. He has a 10-foot by 12-foot rug on the floor.

Rom4ik [11]

1st:
You would multiply 12 x 16 because that's the total area.

2nd:
Then you would multiply 10 x 12 because that's the amount you're subtracting from the total area.

3rd:
(12 x 16) - (10 x 12) =
192 - 120 =

A. 72 ft2

4 0

3 years ago

Plzzzz help!!! quick one ​

Plzzzz help!!! quick one