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2 years ago

5(m+2)-m=2m+3Please I need help

Mathematics

2 answers:

Blababa [14]2 years ago

8 0

Answer:

m=-7/2

Step-by-step explanation:

(5 • (m + 2) - m) - (2m + 3) = 0

2m + 7 = 0

3.1 Solve : 2m+7 = 0

Subtract 7 from both sides of the equation :

2m = -7

Divide both sides of the equation by 2:

m = -7/2 = -3.500

amid [387]2 years ago

4 0

Answer

5(m+2)-m=2m+3

5m+10-m=2m+3

5m-2m-m=-10+3

3m-m=-10+3

2m=-7

m= -7/2

m= -3.5

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nata0808 [166]

Answer: 7 rides

Step-by-step explanation:

Since it takes $4 to enter the fair, you have

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$17.50/$2.50 = 7 rides

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7 0

3 years ago

1.Encuentra la ecuación de la circunferencia que tiene como ecuación ordinaria (x-4)² + (y+5)²= 25 2- encuentra la ecuación gene

rodikova [14]

Responder:

1) x² + y²-8x + 10y + 16 = 0

2) x² + y² + x + 18y + 33 = 0

Explicación paso a paso:

A partir de la pregunta, debemos expresar la ecuación en la forma estándar de un círculo expresado como;

x² + y² + 2gx + 2fy + c = 0 donde;

(-g, -f) es el centro.

1) Para la ecuación (x-4) ² + (y + 5) ² = 25

Expande el paréntesis;

(x-4) ² + (y + 5) ² = 25

x²-8x + 16 + y² + 10x + 25 = 25

x²-8x + 16 + y² + 10y + 25-25 = 0

Recopile términos similares;

x² + y²-8x + 10y + 16 + 0 = 0

x² + y²-8x + 10y + 16 = 0

Por lo tanto, la ecuación requerida es x² + y²-8x + 10y + 16 = 0

2) Para la expresión (x + 1) ² + (y + 9) ² = 49

x² + x + 1 + y² + 18y + 81 = 49

x² + x + 1 + y² + 18y + 81-49 = 0

Recopile términos similares;

x² + y² + x + 18y + 82-49 = 0

x² + y² + x + 18y + 33 = 0

Por tanto, la ecuación requerida es x² + y² + x + 18y + 33 = 0

4 0

3 years ago

Help me please pretty

LiRa [457]

x=-y/3 +9 i believe that should help you

6 0

3 years ago

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lbvjy [14]

Answer:

$\sf \: \fbox{Option C) \: The salary of B is 6000₹}$

Step-by-step explanation:

Let the salary or A is x and salary of B is y.

now,

Condition one,The sum of 3/4th of A’s salary and 5/3rd of B’s salary is ₹16,000.

writing above statement in equation form,

$\sf \frac{3x}{4} + \frac{5y}{3} = 16000$

Multiplying above equation with twelve,

$\sf \frac{3x}{4} + \frac{5y}{3} = 16000 \\ \sf \frac{12 \times 3x}{4} + \frac{12 \times 5y}{3} = 16000 \times 12 \\ \sf \fbox{9x + 20y = 192000} \rightarrow eq. 1$

and condition two,

The difference of their salaries is ₹2000

$\sf \: x - y = 2000$

Multiplying above equation with 20

$\sf \fbox{\: 20x -20y = 40000} \rightarrow eq.2$

On adding equation 1 and equation 2,

$\sf9x + \cancel{20y} = 192000 \\ \sf 20x - \cancel{20y} = 40000 \\ \hline \sf 29x + 0y = 232000 \\ \sf x = \frac{232000}{29} \\ \sf \: \fbox{x = 8000₹}$