Answer:
6/7 = 66/77
9/11 = 63/77
6/7 is greater than 9/11
Step-by-step explanation:
To give fractions a common denominator you must find the LCM(lowest common multiple) of this two denominators.
So, we have 7 and 11. You must find a multiple 7 and 11 share. This means that the number must be divisible by 7 and 11. The LCM for 7 and 11 is 77.
Now we make both the denominators 77.
Now look at the numerators. Look at 6/7. We multipled 7 by 11 to get 77. Therefore, we must also multiply 6 by 11.
Now we have, 66/77
Do the same with the other fraction but other way around:
11 x 7 so
9 x 7 = 63
So,
63/77
So 6/7 is now 66/77 and 9/11 is now 63/77
Now compare:
66 > 63
66 is bigger so 6/7 is greater.
6/7 is greater than 9/11
Answer:
B
Step-by-step explanation:
logₓ 7 = 3
x³ = 7
Take cube root both sides
![x= \sqrt[3]{7}](https://tex.z-dn.net/?f=x%3D%20%5Csqrt%5B3%5D%7B7%7D)
(5x-3)/4 = x/3 +1
5x-3 = 4x/3 +4
5x - 4x/3 = 7
(11/3)x = 7
x = 7/(11/3) = 21/11
Answer:
Alright well Graph the absolute value using the vertex and a few selected points
X: -3, -2, -1, 0, 1
Y: -5, -2, 1, -2, -5 . Hope this helps :)
Step-by-step explanation: