Answer:
Step-by-step explanation:
It starts at 1 adds 1 which got you 2 , then 1 plus 2, is 3, then 2 plus 3 is 5, you get it?
The range of the function 8x + y = -3 at the domain {−3, 1, 2, 4} is {21, -11, -19, -35}
<h3>How to determine the range of the function?</h3>
From the question, we have the following equation that can be used in our computation:
8x + y = -3
Start by making the variable y the subject of the formula
So, we have
y = -8x - 3
Using the domain = {−3, 1, 2, 4} the values in the range are calculated as follows
y = -8 x -3 - 3 = 21
y = -8 x 1 - 3 = -11
y = -8 x 2 - 3 = -19
y = -8 x 4 - 3 = -35
When these values are combined, we have the notation to be:
{21, -11, -19, -35}
So, the range is {21, -11, -19, -35}
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<u>Complete question</u>
What is the answer to this question? 8x+y=-3
domain = {−3, 1, 2, 4}
Write the range of y using set notation.
Answer:
Step-by-step explanation:
B. A coordinate plane has an x axis from 0 to 5 in increments of 1 and a y axis from 0 to 5 in increments of 1. Point A (3,1) is plotted 3 units to the right and 1 unit above the origin. Point B (0,3) is plotted 3 units above the origin. Point C (1,3) is plotted 1 unit to the right and 3 units above the origin.
You are given the hypotenuse and angle F, DE is the leg opposite to angle F, so use sin to solve this problem.
sinF=DE/DF
DE=DF*sinF=55*sin49=41.51