Answer:
D. If the P-value for a particular test statistic is 0.33, she expects results at least as extreme as the test statistic in exactly 33 of 100 samples if the null hypothesis is true.
D. Since this event is not unusual, she will not reject the null hypothesis.
Step-by-step explanation:
Hello!
You have the following hypothesis:
H₀: ρ = 0.4
H₁: ρ < 0.4
Calculated p-value: 0.33
Remember: The p-value is defined as the probability corresponding to the calculated statistic if possible under the null hypothesis (i.e. the probability of obtaining a value as extreme as the value of the statistic under the null hypothesis).
In this case, you have a 33% chance of getting a value as extreme as the statistic value if the null hypothesis is true. In other words, you would expect results as extreme as the calculated statistic in 33 about 100 samples if the null hypothesis is true.
You didn't exactly specify a level of significance for the test, so, I'll use the most common one to make a decision: α: 0.05
Remember:
If p-value ≤ α, then you reject the null hypothesis.
If p-value > α, then you do not reject the null hypothesis.
Since 0.33 > 0.05 then I'll support the null hypothesis.
I hope it helps!
A = v/t Multiply both sides by t
A(t) = v Divide both sides by A
t = v / A
Option A. зу + 12 is the right answer
Step-by-step explanation:
The substitution method consists of finding the value of a variable from one equation and then putting it into another equation to find the value of other variable.
Given equations are:
We have to isolate x in the 2nd equation
Multiplying equation by -1
Subtracting 3y from both sides
Hence,
Option A. зу + 12 is the right answer
Keywords: linear equations, Variables
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85/35 = 2.43% because that is the percent you would need to multiple by
