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emmasim [6.3K]
3 years ago
13

How do you find the derivative of y=ln(cos(x))y=ln(cos(x)) ?

Mathematics
1 answer:
makkiz [27]3 years ago
7 0
y=ln(cosx)\\\\We\ know:\\(lnx)'=\frac{1}{x}\ and\ (cosx)'=-sinx\ and\ \{f[g(x)]\}'=f'[g(x)]\cdot g'(x)\\\\therefore:\\\\y'=\frac{1}{cosx}\cdot(-sinx)=-\frac{sinx}{cosx}=-tanx
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A certain recipe calls for 3 tablespoons of an ingredient in 22 fl oz of liquid. How
dolphi86 [110]

Answer:

-11x-7=-3x^2-11x-7=-3x^2-11x-7=-3x^2-11x-7=-3x^2-11x-7=-3x^2-11x-7=-3x^2-11x-7=-3x^2-11x-7=-3x^2-11x-7=-3x^2-11x-7=-3x^2-11x-7=-3x^2

Step-by-step explanation:

-11x-7=-3x^2-11x-7=-3x^2-11x-7=-3x^2-11x-7=-3x^2-11x-7=-3x^2

5 0
2 years ago
Use the X method to find the solutions of<br> 62 + 2x - 20 = 0.
inysia [295]

Answer:

x = -21

Step-by-step explanation:

62 + 2x - 20 = 0.

Combine like terms

42 +2x =0

Subtract 42 from each side

42-42 +2x = 0-42

2x = -42

Divide each side by 2

2x/2 = -42/2

x = -21

3 0
3 years ago
Read 2 more answers
3. In ΔABC, AB = 5 inches and BC = 3 inches. Which of the choices represents all possible values for AC, in inches?
Nonamiya [84]

Answer:

2< AC<8

Step-by-step explanation:

For a triangle to exits sum of two sides must always be greater than the the third side

⇒ AC<  AB+ BC =5+3=8 in

⇒AC<8 in

Also, the  difference of the two sides must be smaller than the length of third side

⇒ AC> | AB-BC| = |5-3| =2

AC> 2 in

therefore,  we can say  2< AC<8. Hence, AC can takes 3,4,5,6 values

4 0
3 years ago
What is the volume of a cone (in cubic inches) of radius 5 inches and height 3
beks73 [17]

Answer:

78.54 cm^3

Step-by-step explanation:

I think thats the answer

6 0
3 years ago
Margo wants to convince her father to change her curfew from 9 P.M. to 10 P.M. She gathers data on curfew times from a random sa
Irina-Kira [14]

Answer: No; Most students have a curfew of 9 pm or earlier

3 0
3 years ago
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