4 years ago

How do you find the derivative of y=ln(cos(x))y=ln(cos(x)) ?

1 answer:

7 0

$y=ln(cosx)\\\\We\ know:\\(lnx)'=\frac{1}{x}\ and\ (cosx)'=-sinx\ and\ \{f[g(x)]\}'=f'[g(x)]\cdot g'(x)\\\\therefore:\\\\y'=\frac{1}{cosx}\cdot(-sinx)=-\frac{sinx}{cosx}=-tanx$

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Vedmedyk [2.9K]

Answer:

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Step-by-step explanation:

Given $(x-2)^2=9$ , to solve for $x$ , our goal is to isolate $x$ .

Take the square root of both sides:

$x-2=\pm\sqrt{9},\\x-2=\pm 3$ (recall that $3^2=(-3)^2=9$ ).

Therefore, we have two cases:

$\begin{cases}x-2=3,x=\boxed{5} \\x-2=-3, x=\boxed{-1}\end{cases}$

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3 years ago

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alukav5142 [94]

A, B , D are point of line t, which is contained in plane P.

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7nadin3 [17]

Answer:

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3 years ago

10x - 10y = 1 x = y - 3 solve the system of equations by substitution. a. (-29/20, 31/20) b. (1/2, 2/5) c. no solution d. coinci

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First you'd substitute x= y-3 in the first equation.

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The y's cancel each other out, so you're left with -30= 1. That means there's no solution :)

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3 years ago

What is the common difference between successive terms in the sequence?

Alborosie

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