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emmasim [6.3K]
3 years ago
13

How do you find the derivative of y=ln(cos(x))y=ln(cos(x)) ?

Mathematics
1 answer:
makkiz [27]3 years ago
7 0
y=ln(cosx)\\\\We\ know:\\(lnx)'=\frac{1}{x}\ and\ (cosx)'=-sinx\ and\ \{f[g(x)]\}'=f'[g(x)]\cdot g'(x)\\\\therefore:\\\\y'=\frac{1}{cosx}\cdot(-sinx)=-\frac{sinx}{cosx}=-tanx
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