Let width and length be x and y respectively.
Perimeter (32in) =2x+2y=> 16=x+y => y=16-x
Area, A = xy = x(16-x) = 16x-x^2
The function to maximize is area: A=16 x-x^2
For maximum area, the first derivative of A =0 => A'=16-2x =0
Solving for x: 16-2x=0 =>2x=16 => x=8 in
And therefore, y=16-8 = 8 in
Answer:
x=0
Step-by-step explanation:
0-0=0
Answer:
x=-4 y=5
Step-by-step explanation:
Rewrite equations:
x=−4y+16;3x+4y=8
Step: Solvex=−4y+16for x:
x=−4y+16
Step: Substitute−4y+16forxin3x+4y=8:
3x+4y=8
3(−4y+16)+4y=8
−8y+48=8(Simplify both sides of the equation)
−8y+48+−48=8+−48(Add -48 to both sides)
−8y=−40
−8y
−8
=
−40
−8
(Divide both sides by -8)
y=5
Step: Substitute5foryinx=−4y+16:
x=−4y+16
x=(−4)(5)+16
x=−4(Simplify both sides of the equation)
Answer:
x=−4 and y=5
Answer:
I KNOWW THE ANSWER!!
Step-by-step explanation:
