18 (goes down): 17, 16, 15
12 (goes up): 13, 14, 15
The shortest height at which the two stacks of boxes will be the same height is 15.
Hope I was able to help!
Answer:
Option C
Step-by-step explanation:
6x² +5x + 1
6x² + 3x + 2x + 1
3x(2x + 1) + 1(2x + 1)
(3x + 1)(2x + 1)
cant understand your language can you translate in English
Let
b-----------> the length side of the square box
h------------> the height of the box
SA---------> surface area of the box
we know that
[volume of the box]=b²*h
volume=256 in³
b²*h=256-------> h=256/b²-----> equation 1
surface area of the box=area of the base+perimeter of base*height
area of the base=b²
perimeter of the base=4*b
surface area=b²+(4*b)*h------> SA=b²+4*b*h-----> equation 2
substitute equation 1 in equation 2
SA=b²+4*b*[256/b²]-----> SA=b²+1024/b-----> SA=(b³+1024)/b
the answer is
the formula of the volume of the box is V=b²*h-----> 256=b²*h
the formula of the surface area of the box are
SA=b²+4*b*h
SA=(b³+1024)/b
Answer:
I think it is C
Step-by-step explanation:
