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Harrizon [31]
2 years ago
12

There are 380 lightbulbs lined up in a row in a long room each bulb has his own switch and it’s currently switched off each bulb

is number constitutionally from 1 to 380 you first flip every switch then you flip the switch on every second bulb you then flip the switch on every third bulb this continues until you have gone through the process 380 times
Mathematics
1 answer:
BARSIC [14]2 years ago
6 0

Flipping the bulbs is an illustration of sequence and patterns

19 bulbs would remain on.

<h3>How to determine the number of bulbs that will be on</h3>

The sequence of turning the bulbs off and on, would change the state of the bulbs until the 380th process.

While changing the state of the bulbs, the bulb at the perfect square positions would remain on.

There are 19 perfect square numbers between 1 and 380 (inclusive)

Hence, 19 bulbs would remain on.

Read more about sequence and patterns at:

brainly.com/question/15590116

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What is the smallest prime number p such that
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The smallest prime number of p for which p^3 + 4p^2 + 4p has exactly 30 positive divisors is 43.

<h3>What is the smallest prime number of p for which p must have exactly 30 positive divisors?</h3>

The smallest number of p in the polynomial equation p^3 + 4p^2 + 4p for which p must have exactly 30 divisors can be determined by factoring the polynomial expression, then equating it to the value of 30.

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Now, to get exactly 30 divisor.

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Therefore, we can have an equation p + 2 = p₁ × p₂²

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