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Effectus [21]
2 years ago
11

Which is the standard form of the equation of the parabola that has a vertex of (-4,-3) and a directrix of x = 2?

Mathematics
1 answer:
maxonik [38]2 years ago
6 0

Answer:

C.

Step-by-step explanation:

i took the test

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Find the GCF for 15az and 25az
SOVA2 [1]

Answer:

The GCF for 15az and 25az is marked below.

15az = 3*5*a*z

25ab - 5*5*a*b

GCF = 5a

Step-by-step explanation:

Answers above! Hoped this helped :)

5 0
2 years ago
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If triangle CDE is dilated by a scale factor of 1/5 with a center of dilation at vertex E, what is the area of triangle C'D'E'?
timurjin [86]
The correct answer would be Choice B: 4 square units.

When the scale factor is 1/5, that means the lengths of the sides are 1/5 of the original size. So instead of having a base of 20 and height of 10, the new triangle has a base of 4 and a height of 2.

The area of the triangle is: (4 x 2) / 2 = 4
8 0
3 years ago
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Find the equation of the line with Slope = -4 and passing through (-1,8). Write your equation in the form
Thepotemich [5.8K]

Answer:

y= -4x+4

Step-by-step explanation:

y=mx+b

where x=-1, y=8, and m=-4

8=(-4)(-1)+b

8=4+b

4=b

Thus, y= -4x+4

8 0
2 years ago
Find the standard form of the equation of the parabola with a focus at (0, 8) and a directrix at y = -8.
Gala2k [10]
Vertex is directly in middle of directix and focus

distance from 8 to -8 is 16
16/2=8
so 8 below focus (since 8>-8) is the point (0,0
vertex is (0,0)
nice

it opens up because focus is above directix
also it goes up down so
4p(y-k)=(x-h)^2
(h,k) is veretx
we got that (h,k) is (0,0)
and p is distance from vertex to focus which is 8
so
4(8)(y-0)=(x-0)^2
32y=x^2
y=(1/32)x^2
5 0
3 years ago
Can someone please answer this for me
djverab [1.8K]

Answer:

C

Step-by-step explanation

the numbers are decreasing -3

4 0
2 years ago
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