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sasho [114]
2 years ago
8

The table shows the average chick weight in grams of sixteen different species of birds.

Mathematics
1 answer:
Amanda [17]2 years ago
4 0

Answer:

1# - 5g is the lighest weight.

2# - 3 of the weights are less than 10 grams.

Step-by-step explanation:

So, lets start with our first question, which chicken weight is the least?

To answer this, all we have to do is read through the table, and find the <u>smallest</u> number.

We see that 5 is the smallest number on the graph, as seen in the first image I attached below :3

So the answer to the first question is 5g is the smallest weight(we add the g at the end because the unit of measurement is in grams(g).)

Now we have question 2. How can we go about answering this?

We go through each weight in the chart, and tally up how many are <u>below 10 grams</u>.

After looking at each of the 16 weights, we see that 6, 7, and 5 are the 3 weights that are less than 10. We can see this in the second image I attached below.

So your two answers are:

Question #1 = <u>5 grams</u>

Question #2 = <u>3 of the weights</u>

Hope this helps! :3

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kaheart [24]
I would say 8.55, regardless you're talking about the median or not.
4 0
3 years ago
Read 2 more answers
A 55m and 35m broad park is surrounded by a 2.5m wide path.
daser333 [38]

Step-by-step explanation:

☄ \underline {\underline{ \text{Given}}} :

  • Length of a park ( l ) = 55 m
  • Breadth of a park ( b ) = 35 m
  • Width running outside the park ( d ) = 2.5 m
  • Rate of paving the path with stones = Rs 120 per sq.metre

☄ \underline{ \underline{ \text{To \: find}}}:

  • Area of the park
  • Cosy of paving the path with stones at Rs 130 per sq.metre

☄ \underline{ \underline{ \text{Solution}}} :

Part 1 : \boxed{\text{Area \:of \:a \:path \: running \:outside = 2d(l + b + 2d)}}

plug the known values and simplify :

⟹ \sf{2 \times 2.5(55 + 35 + 2 \times 2.5)}

⟹ \sf{5  \times 95}

⟹ \sf{475 \:  {m}^{2} }

Part 2 : \boxed{ \sf{Total \: cost = Area \: of \: paths \:  \times  Rate}}

⟹ \sf{475  \times 120}

⟹\sf{Rs \: 57000}

\purple{ \boxed{ \boxed{ \sf{ \tt{⟿ \: Our \: final \: answer : (i) = 475 \:  {m}^{2}   \:  and \: (ii ) = Rs \: 57000}}}}}

Hope I helped ! ♡

Have a wonderful day /night ツ

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7 0
3 years ago
Which of the following is not a Pythagorean triple?
Ierofanga [76]

Answer:

  (7, 24, 26)

Step-by-step explanation:

A Pythagorean triple must have an odd number of even numbers. The triple (7, 24, 26) is not a Pythagorean triple.

_____

<em>Additional comment</em>

For an odd integer n, a triple can be formed as ...

  (n, (n²-1)/2, (n²+1)/2)

That is, the following will be Pythagorean triples.

  • (3, 4, 5)
  • (5, 12, 13)
  • (7, 24, 25)
  • (9, 40, 41)
  • (11, 60, 61)

Another series involves even numbers and numbers separated by 2:

  (2n, n²-1, n²+1)

  • (8, 15, 17)
  • (12, 35, 37)
  • (16, 63, 65)

In this list, if n is not a multiple of 2, the triple will be a multiple of one from the odd-number series.

It is a good idea to remember a few of these, as they tend to show up in Algebra, Geometry, and Trigonometry problems.

8 0
2 years ago
The area of the city of Vancouver is 115 km^2. if the shape of Vancouver is approximately a square, how wide is the city of Vanc
Dmitry [639]

Answer:

The wide of the city is 10.7km

Step-by-step explanation:

To solve this we first have to know the formula to calculate the area of ​​a square

a = area = 115 km²

s = side

a = s * s

now we replace with the known values

115 km² = s * s

115 km² = s²

√(115 km²) = s

10.724km = s

Round to the nearest tenth

s = 10.724km = 10.7km

The wide of the city is 10.7km

5 0
3 years ago
Jacob went camping with his family. At 7:15 A.M., Jacob set out to go fishing. It took 1 hour and 45 minutes to hike to the lake
GREYUIT [131]

Answer:

  1. 7:15 A.M.
  2. 1 hour and 45 min = 105 min
  3. 3 hour 45 min= 225 min
  4. 1 hour and 15 min = 105 min
  5. 105(2)+ 225= 435 min= 7 hours and 25 min.
  6. Add that to the original total you get 14:40 P.M
7 0
3 years ago
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