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2 years ago

8

The table shows the average chick weight in grams of sixteen different species of birds.

1 answer:

Amanda [17]2 years ago

4 0

Answer:

1# - 5g is the lighest weight.

2# - 3 of the weights are less than 10 grams.

Step-by-step explanation:

So, lets start with our first question, which chicken weight is the least?

To answer this, all we have to do is read through the table, and find the <u>smallest</u> number.

We see that 5 is the smallest number on the graph, as seen in the first image I attached below :3

So the answer to the first question is 5g is the smallest weight(we add the g at the end because the unit of measurement is in grams(g).)

Now we have question 2. How can we go about answering this?

We go through each weight in the chart, and tally up how many are <u>below 10 grams</u>.

After looking at each of the 16 weights, we see that 6, 7, and 5 are the 3 weights that are less than 10. We can see this in the second image I attached below.

So your two answers are:

Question #1 = <u>5 grams</u>

Question #2 = <u>3 of the weights</u>

Hope this helps! :3

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The diagram below represents the net of a triangular prism. What is the surface area of the triangular prism?

AleksandrR [38]

Answer:

(C)

Step-by-step explanation:

The diagram is divided ninto 5 parts that is rectangles ABCD, CHGD, GFEH and triangles CIH and DGJ.

Area of rectangle ABCD= $l{\times}b$

= $12{\times}6=72cm^{2}$

Area rectangle CDHG= $l{\times}b$

= $12{\times}8=96cm^{2}$

Area rectangle HGFE= $l{\times}b$

= $10{\times}12=120cm^{2}$

Area of triangles CIH and DIG= $2{\times}\frac{1}{2}{\times}b{\times}h$

= $6{\times}8=48cm^{2}$

Surface area of the triangular prism=Area of rectangle ABCD+Area rectangle CDHG+Area rectangle HGFE+Area of triangles CIH and DIG

= $72+96+120+48=336cm^{2}$

Hence, option C is correct.

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Find the linear approximation of the function g(x) = 3 1 + x at a = 0. g(x) ≈ Correct: Your answer is correct. Use it to approxi

EleoNora [17]

Answer:

$3.296x+3$

2.835

3.330

Step-by-step explanation:

$g(x) = 3^{1+x}$

Let the linear approximation be L(x) at a = 0. This is given by

$L(x) = g(a) + g'(a)(x-a)$

$g'(x)$ is the derivative of $g(x)$ . To find this, we use the form

If $f(x) = a^x$ , then $f'(x) =a^x\ln a$

By doing this and applying chain rule for the power (which is a function of x), we have

$g'(x) = 3^{1+x}\ln 3$

Then

$g'(0) = 3^{1+0}\ln 3 = 3.296$

Also $g(0) = 3^{1+0} = 3$

Hence $L(x) = 3+(x-0)\times3.296 = 3.296x + 3$

For $3^{0.95}$ , $1+x = 0.95$ and $x=-0.05$

Using this in $L(x)$ ,

$3^{0.95} = 3.296(-0.05) + 3 = 2.835$

For $3^{1.1}$ , $1+x = 1.1$ and $x=0.1$

Using this in $L(x)$ ,

$3^{1.1} = 3.296(0.1) + 3 = 3.330$

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3 years ago