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Elenna [48]
3 years ago
5

What is squareroot of 122?

Mathematics
2 answers:
Mrrafil [7]3 years ago
7 0

Step-by-step explanation:

it's

√122 or 10√22

_____________________________

frosja888 [35]3 years ago
5 0
This is what shows when you square root “122” —> 11.045… but I’m not sure if you need to round it or not so this is not rounded 11.045
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Suppose S is between R and T. Use the Segment Addition Postulate to solve for the variable. Round to three decimal places. RS =
Olegator [25]

Answer:

The variable y = 2.100

Step-by-step explanation:

Here, we are told to solve for the variable y.

We are asked to use the segment addition postulate. In summary, the postulate is of the opinion that given 3 points X,Y and Z, we can only say that these 3 points are collinear(lie on the same line) if they obey the formula below;

XZ = XY + YZ

Now, we have that S is between R and T.

Mathematically that means;

RT = RS + ST

from the question, we are told that RT = 26, RS = 9y-2 and ST = y + 7

Now, insert these values into the alphabetical equation;

26 = (9y-2) + (y + 7)

26 = 9y-2 + y + 7

26 = 9y+y -2 + 7

26 = 10y + 5

26-5 = 10y

10y = 21

y = 21/10

y = 2.1

Which is y = 2.100 to three decimal places

7 0
3 years ago
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boyakko [2]
The table with x=0, 1,2 y= 2,-1,-4
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3 years ago
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Find the value of yy in each equation. Explain how you determined the value of y.
Hitman42 [59]

Answer:

a) 3

b) 9

c) 81

d) x

Step-by-step explanation:

We know the properties of log function as:

1) log(AB) = log(A) + log(B)

2) \log(\frac{A}{B}) = \log(A)+\log(B)

3) log(aᵇ) = b × log(a)

also,

4) \log_b(a)=\frac{\log(a)}{\log(b)}

Given:

a. y = 3^{\log_3(3)}

Now,

taking log both sides, we get

log(y) = \log(3^{\log_3(3)})

using 3, we get

log(y) = log₃(3) × log(3)

using 4, we get

log(y) =  \frac{\log(3)}{\log(3)} × log(3)

or

log(y) =  1 × log(3)

taking anti-log both sides

y = 3

b. y = 3^{log_3(9)}

Now,

taking log both sides, we get

log(y) = \log(3^{\log_3(9)})

using 3, we get

log(y) = log₃(9) × log(3)

using 4, we get

log(y) =  \frac{\log(9)}{\log(3)} × log(3)

or

log(y) = log(9)

taking anti-log both sides

y = 9

c. y = 3^{\log_3(81)}

Now,

taking log both sides, we get

log(y) = \log(3^{\log_3(81)})

using 3, we get

log(y) = log₃(81) × log(3)

using 4, we get

log(y) =  \frac{\log(81)}{\log(3)} × log(3)

or

log(y) =  log(81)

taking anti-log both sides

y = 81

d. y = 3^{\log_3(x)}

Now,

taking log both sides, we get

log(y) = \log(3^{\log_3(x)})

using 3, we get

log(y) = log₃(x) × log(3)

using 4, we get

log(y) =  \frac{\log(x)}{\log(3)} × log(3)

or

log(y) =  log(x)

taking anti-log both sides

y = x

3 0
3 years ago
2<br> 1 point<br> Is (6, -2) a solution to 6x – 4y &gt; 24?<br> no?<br> yes?
jok3333 [9.3K]

Answer:

Yes, (6, -2) is a solution.

Step-by-step explanation:

See if it is a solution by plugging in the x and y values into the inequality. If it makes the inequality true, it is a solution. If it makes it false, it is not a solution.

6x - 4y > 24

6(6) - 4(-2) > 24

Simplify:

36 + 8 > 24

44 > 24

This is true, meaning that (6, -2) is a solution to the inequality.

Yes, (6, -2) is a solution.

3 0
3 years ago
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