Question

Hannah has information about an object in circular orbit around Earth. MEarth = 6. 0 × 1024 kg G = 6. 67 × 10–11 StartFraction m Superscript 3 Baseline over kilograms times s Superscript 2 Baseline EndFraction. Rearth=6. 0 x 106 m Using the information given what does Hannah need in order to calculate the tangential speed of the orbiting object ? the mass of the orbiting object the distance of the orbiting object to Earth the orbital period of Earth the radius of Earth.

Answer 1

In order to calculate the tangential speed of the orbiting object   Hannah need the distance of the orbiting object to Earth.

What is the tangential speed of the object?

The tangential speed of an object is the linear component of the speed, which is moving in a circular path.

In terms of  the gravitation constant, the tangential speed can be given as,

$v=\sqrt{\dfrac{Gm}{r}}$

Here, {G} is the gravitation constant, (m) is the mass and (r) is the radius.

Hannah has information about an object in circular orbit around Earth.

The mass of the earth is.

$m_E=6. 0 \times10^{24} kg$

The value of gravitational constant is,

$G=6. 67\times 10{-11}\rm Nm^2/kg^2$

The radius of the earth is,

$r_E=6. 0 \times 10^6 \rm m$

Here, only the distance of the orbiting object to Earth is need to find the tangential speed of the object.

Hence, in order to calculate the tangential speed of the orbiting object   Hannah need the distance of the orbiting object to Earth.

Learn more about the tangential speed here;

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