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3 years ago

Which of the following are solutions to the equation below?4x^2-12x+9=5

Mathematics

2 answers:

timofeeve [1]3 years ago

8 0

Answer:

$x=\frac{-\sqrt{5}+3}{2}$ and $x=\frac{\sqrt{5}+3}{2}$

Step-by-step explanation:

$4x^2-12x+9=5$

To solve for x we need to make right hand side 0

Subtract 5 on both sides

$4x^2-12x+4=0$

Divide whole equation by 4

$x^2-3x+1=0$

Apply quadratic formula to solve for x

$x=\frac{-b+-\sqrt{b^2-4ac}}{2a}$

the value of a=1, b=-3 and c=1

$x=\frac{-(-3)+-\sqrt{(-3)^2-4(1)(1)}}{2(1)}$

$x=\frac{3+-\sqrt{5}}{2}$

$x=\frac{-\sqrt{5}+3}{2}$ and $x=\frac{\sqrt{5}+3}{2}$

Damm [24]3 years ago

5 0

$4x^2-12x+9=5\\4x^2-12x+9-5=0\\4x^2-12x+4=0 \ \ \ |:4\\x^2-3x+1=0 \\ \\ x= \cfrac{3б \sqrt{(-3)^2-4} }{2}= \cfrac{3б \sqrt{9-4} }{2}= \cfrac{3б \sqrt{5} }{2} 

$

Correct answers are C and E

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Answer:

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Step-by-step explanation:

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This basically means:

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Since we don't know what $log_{100}20$ is equal to, we will say $log_{100}20$ = x

So to solve for $log_{100}20$ = x, you do the same thing. (convert to exponential form)

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Now you will notice that both of these equations are equal to 20.

Since 20 = 20,

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Because you have the same base, you can just ignore the 10s and focus on the exponents. So you get:

2x = 1.301

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