Let r = radius, h = height and l = slant height
Lateral area = rlpi
But l = sqrt(r^2 + h^2)
Lateral area = r sqrt( r^2 + h^2) pi = 20 pi..................(1)
Total area = r sqrt( r^2 + h^2) pi + r^2 pi = 36pi......(2)
Subtract (1) from (2)
r^2 pi = 16 pi
r^2 = 16
r = 4 cm
Put this value in (1) to find h
4sqrt(4^2 + h^2) pi = 20 pi
sqrt(16 + h^2) = 5
Square both sides
16 + h^2 = 25
h^2 = 9
h = 3 cm
Now that we know h and r we can find the volume
V = 1/3 pi r^2 h
= 1/3 pi (4^2)(3)
<span>= 16 pi cm^3 .........( = 50.27 cm^3)
I hope my answer has come to your help. God bless and have a nice day ahead!
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A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3). This can be obtained by putting the ΔABC's vertices' values in (x, y-3).
<h3>Calculate the vertices of ΔA'B'C':</h3>
Given that,
ΔABC : A(-6,-7), B(-3,-10), C(-5,2)
(x,y)→(x,y-3)
The vertices are:
- A(-6,-7 )⇒ (-6,-7-3) = A'(-6, -10)
- B(-3,-10) ⇒ (-3,-10-3) = B'(-3,-13)
- C(-5,2) ⇒ (-5,2-3) = C'(-5,-1)
Hence A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3).
Learn more about translation rule:
brainly.com/question/15161224
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Answer:
B is answer
Step-by-step explanation:
Answer:
(-1, 3)
Step-by-step explanation:
x - 5y = -16 [Equation 1]
-x + 3y = 10 [Equation 2]
<u>Adding both equations</u>
- x - x - 5y + 3y = -16 + 10
- -2y = -6
- y = 3
- x - 5(3) = -16
- x - 15 = -16
- x = -1
<u>Solution</u> : (-1, 3)
The Solution:
The correct answer is [option B]
Given:
Required:
To determine the inequality represented by the given number line.
