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timama [110]
2 years ago
5

find the midpoint of AB. A(-9,3), B(7,-8). write an equation perpendicular to AB passes through the midpoint

Mathematics
1 answer:
steposvetlana [31]2 years ago
3 0

Step-by-step explanation:

the solution is in the picture

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Triss [41]

Answer:

10/1 +54/-6

Step-by-step explanation:

Is this the answer?

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Free_Kalibri [48]

Answer:

A) 113 m²

Step-by-step explanation:

Use the formula for area of a circle.

Area of a circle = πr²

π = pi = 3.14 (rounded)

r = radius

² = the power of 2, or the radius (in this case) multiplied by itself.

Note that the radius is given, and it is 6. Plug in 6 for the radius:

A (circle) = π(6)²

First, solve the power. Multiply 6²:

6² = 6 * 6 = 36

Next, multiply 36 with π (3.14):

36 x 3.14 = 113.04

A) 113 m² is your closest answer.

~

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3 years ago
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Tan(θ)/sec(θ) − cos(θ)
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Sin(theta)- cos(theta)
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The employees of two companies were asked how many times they checked their email during weekends. The table below shows the num
tekilochka [14]
Q1 of company A = 2.5
Q3 of company A = 8
Interquatile range = (Q3 - Q1)/2 = (8 - 2.5)/2 = 5.5/2 = 2.75

Q1 of company B = 2
Q3 of company B = 5.5
Interquatile range = (5.5 - 2)/2 = 3.5/2 = 1.75

Therefore, t<span>he interquartile range for Company A employees is 2 more than the interquartile range for Company B employees.</span>
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A train leaves Philadelphia at 2:00 PM. A second train leaves the same city in the same direction at 4:00 PM. The second train t
polet [3.4K]

Answer: First train speed shall be 42 mi/hr

Second train speed shall be 84 mi/hr

Yes it is the valid answer, it gets annoying when almost everyone enters the wrong answer for a good laugh. Either way, hope this helps! Have a spectacular day.

Step-by-step explanation:

What is the 1st train's head start in miles?

Let +s+ = the speed of the 1st train in mi/hr

From 2PM to 4PM is 2 hrs

+d%5B1%5D+=+s%2A2+

---------------------

Let +d+ = distance the 2nd train travels until

it overtakes the 1st train

From 4PM to 6PM is 2 hrs

Start time when the 2nd train leaves

---------------------

Equation for 1st train:

(1) +d+-+2s+=+s%2A2+

Equation for 2nd train:

(2) +d+=+%28+s%2B42+%29%2A2+

--------------------

Substitute (2) into (1)

(1) +%28+s%2B42+%29%2A2+-+2s+=+s%2A2+

(1) +2s+%2B+84+-+2s+=+2s+

(1) +2s+=+84+

(1) +s+=+42+

and

+s%2B+42+=+42+%2B+42+

+s+%2B+42+=+84+

------------------

The 1st train's speed is 42 mi/hr

The 2nd train's speed is 84 mi/hr

---------------------------

check:

(2) +d+=+%28+s%2B42+%29%2A2+

(2) +d+=84%2A2+

(2) +d+=+168+

and

(1) +d+-+2s+=+s%2A2+

(1) +d+-+2%2A42+=+42%2A2+

(1) +d+=+84+%2B+84+

(1) +d+=+168+

8 0
3 years ago
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