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2 years ago

Need helppp hurry please i only have 1 check answer

Mathematics

1 answer:

Angelina_Jolie [31]2 years ago

8 0

Answer: 1

Step-by-step explanation: 3z+6 you subtract 6 from each side which gives u 3z=3 then u divide so 3 divide by 3 is one or just z

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Three times the sum of a number and 4 is 8 less than one-half the number. Write and solve equation to find the number.

gizmo_the_mogwai [7]

3(x+4)=(1/2)x-8 => 3x+12=(1/2)x-8 we will multiply equation with number 2 and we get 6x+12 = x-16 => 6x-x=-16-24 => 5x=-40 => x=-8

Good luck!!!

4 0

3 years ago

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Which of the following could be the graph of a polynomial whose leading term is <img src="https://tex.z-dn.net/?f=-3x%5E4" id="T

OlgaM077 [116]

The leading coefficient is a negative value (-3) so the graph goes down on the right side.

This makes either Graph B or C correct.

Now because the degree ( exponent ) (the ^4) is even both ends of the graph go in the same direction.

This makes Graph B the correct answer.

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4 years ago

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A fruit company delivers its fruit in two types of boxes large and small a delivery of three large boxes and five box that has a

Savatey [412]

Answer:

The weight of large box is 13.25 kilograms and the weight of small box is 6.25 kilograms.

Step-by-step explanation:

Given:

A fruit company delivers its fruit in two types of boxes large and small a delivery of three large boxes and five small boxes that has a total weight of 71 kilograms and a delivery of six large boxes and two small boxes has a total weight of 92 kilograms.

Now, to find the weight of each type of box.

Let the weight of large box be $x$ .

And let the weight of small box be $y.$

A delivery of three large boxes and five small boxes has a total weight of 71 kilograms:

$3x+5y=71\ \ \ .....(1)$

And, the delivery of six large boxes and two small boxes has a total weight of 92 kilograms:

$6x+2y=92\\\\Subtracting\ both\ sides\ by\ 6x:\\\\2y=92-6x\\\\Dividing\ both\ sides \ by\ 2\ we\ get:\\\\y=46-3x\ \ \ \ ......(2)$

Now, substituting the value of $y$ from equation (2) in equation (1):

$3x+5y=71\\\\3x+5(46-3x)=71\\\\$

$3x+230-15x=71\\\\230-12x=71\\\\$

Subtracting 230 on both sides we get:

$-12x=-159$

Dividing both sides by -12 we get:

$x=13.25.$

The weight of large box = 13.25 kilograms.

Now, substituting the value of $x$ in equation (1) we get:

$3x+5y=71\\\\3(13.25)+5y=71\\\\39.75+5y=71\\\\Subtracting\ both\ sides by\ 39.75\ we\ get:\\\\5y=31.25\\\\Dividing\ both\ sides\ by\ 5\ we\ get:\\\\y=6.25.$