Area=legnth times width
so multiply them together use distributive property
a(b+c)=ab+ac so
in this problem
(a+b)(c+d+e)=(a+b)(c)+(a+b)(d)+(a+b)(e)
so
x^2-2 times (2x^2-x+2)=(x^2)(2x^2-x+2)-(2)(2x^2-x+2)=(2x^4-x^3+2x^2)-(4x^2-2x+4)
add like terms
2x^4-x^3+(2x^2-4x^2)-2x+4
2x^4-x^3-2x^2-2x+4
I-1 is the polynomials because I is the linear term and 1 is the constant
Answer:
3
Step-by-step explanation:
To evaluate the expression, we have to substitute the variable in the expression, z, for its stated value. Given that z = 6, substitute 6 for the z in the expression and solve:

Thus, the answer is 3.
Answer:
Third option
Step-by-step explanation:
Because it has to be JKL or LKJ, (see how the K stays in the middle)