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2 years ago

What is the main conflict in "The Night the Bed Fell"?

Mathematics

2 answers:

Iteru [2.4K]2 years ago

8 0

The awnser is d the narrator want to pull you in the book and say his bed fliped over

sooo the awnser is D.

hjlf2 years ago

6 0

The answer is ". d."
.................................................

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Hahahhahahha again thanks for helping!

frosja888 [35]

Answer:

( -1, 5 )

Step-by-step explanation:

I hope this helps!! :)

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2 years ago

a grocery store sign indicates that bananas are 6 for $1.50 and a sign by the oranges indicates that they are 5 for $3.00 find t

Yakvenalex [24]

$3.00/5 = $0.60 * 2 = $1.20 for 2 oranges and $1.50/6 = $0.25 * 2 = $0.50 for 2 bananas TOTAL = $1.70

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2 years ago

Troy is 1.4 meters tall Ena is 54 centimeters shorter How tall is Ena

ser-zykov [4K]

Ena is -1.39 meters tall

54 centimeters = 0.01
0.01 m - 1.4 = 1.39

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2 years ago

Math Question (question shown on image)

Papessa [141]

Answer:

very easy bro the answer is

Step-by-step explanation:

w< or equal to 200

3 0

2 years ago

The number of people arriving for treatment at an emergency room can be modeled by a Poisson process with a rate parameter of fo

Aleonysh [2.5K]

Answer:

a) 0.195 = 19.5% probability that exactly three arrivals occur during a particular hour.

b) 0.762 = 76.2% probability that at least three people arrive during a particular hour

c) 2 people.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Poisson process with a rate parameter of four per hour.

This means that $\mu = 4$ .

(a) What is the probability that exactly three arrivals occur during a particular hour?

This is P(X = 3). So

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 3) = \frac{e^{-4}*4^{3}}{(3)!} = 0.195$

0.195 = 19.5% probability that exactly three arrivals occur during a particular hour.

(b) What is the probability that at least three people arrive during a particular hour?

Either less than three people arrive during a particular hour, or at least three does. The sum of the probabilities of these outcomes is 1. So

$P(X < 3) + P(X \geq 3) = 1$

We want $P(X \geq 3) = 1 - P(X < 3)$ , in which

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)$ . So

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-4}*4^{0}}{(0)!} = 0.018$

$P(X = 1) = \frac{e^{-4}*4^{1}}{(1)!} = 0.073$

$P(X = 2) = \frac{e^{-4}*4^{2}}{(2)!} = 0.147$

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.018 + 0.073 + 0.147 = 0.238$

$P(X \geq 3) = 1 - P(X < 3) = 1 - 0.238 = 0.762$

0.762 = 76.2% probability that at least three people arrive during a particular hour.

c) How many people do you expect to arrive during a 30-min period?

One hour, 4 people

Half an hour = 30 min = 4/2 = 2 people.

6 0

2 years ago