Answer:
kuyky
Step-by-step explanation:
kmjkfhjmk
An equvilent equation
remember you can do anything to an equation as long asyou do it to both sides
assuming yo have
x+y=1 and
x-3y=9
mulitply both by 2
2x+2y=2
2x-6y=18
those are equvilent
ok, solve initial
x+y=1
x-3y=9
multiply first equation by -1 and add to 2nd equation
-x-y=-1
<u>x-3y=9 +</u>
0x-4y=8
-4y=8
divide both sides by -4
y=-2
sub back
x+y=1
x-2=1
add 2
x=3
x=3
y=-2
(3,-2)
if we test it in other one
2x+2y=2
2(3)+2(-2)=2
6-4=2
2=2
yep
2x-6y=18
2(3)-6(-2)=18
6+12=18
18=18
yep
solution is (3,-2)
Fourth one since x is 2 and the y is 1
Answer:
I and IV
Step-by-step explanation:
cosine is positive/greater than 0 in quadrants I and IV. Its just a rule of the unit circle.
Can remember by All Star Trig Class
meaning all the trig funtions are positive in quadrant I
sin is positive in II
tan is positive in III
and cos is positive in IV
5300 and 6000 is the elevation in miles
