Ask question

Ask question

All categories

2 years ago

13

Esmeralda rent a car from a company that race cars by an hour she has a pair nishal fee of $52 and then they charged her $8 per

hour she has $144 available to spend on a car rental what is the greatest number of hours for which she can rent the car

1 answer:

tatuchka [14]2 years ago

7 0

Answer:

11 hours is the most she can afford

Step-by-step explanation:

You might be interested in

Explain how to find coordinates for Q

Vesna [10]

Answer:

Q = (4, - 1)

Step-by-step explanation:

DF is the diameter of the circle with center Q.

So, Q is the midpoint of DF.

By mid point formula.

$Q = \bigg( \frac{1 + 7}{2}, \: \: \frac{3 - 5}{2} \bigg) \\ \\ Q = \bigg( \frac{8}{2}, \: \: \frac{ - 2}{2} \bigg) \\ \\ Q = (4, \: \: - 1)$

6 0

2 years ago

Read 2 more answers

Pls answer before 8:00 pm

Semenov [28]

Answer:225 jeans.

Step-by-step explanation: What we need to do here is convert the number of jeans to a percentage. There were 25 jeans when 50 customers were surveyed and 25 is half of 50 or 50%. This means that if 450 pairs of pants are ordered half of them should be jeans. 450/2 = 225.

8 0

11 months ago

Given that f(x) = 3x + 1 and g(x) = the quantity of 4x plus 2 divided by 3, solve for g(f(0))

Yuliya22 [10]

F(0)=1

g(1)=(4*1+2)/3 = 6/3=2

hope helped

5 0

2 years ago

Read 2 more answers

A certain shop repairs both audio and video components. Let A denote the event that the next

alexdok [17]

Answer:

0.12 is the required probability.

Step-by-step explanation:

We are given the following in the question:

A: next component brought in for repair is an audio component

B: event that the next component is a compact disc player

$B \in A$

$P(A)= 0.6\\P(B) =0.05$

We have to evaluate:

$P(B|A) = \dfrac{P(B\cap A)}{P(A)}\\P(B|A) = \dfrac{P(B)}{P(A)}\\\\P(B|A) = \dfrac{0.05}{0.6} = 0.12$

0.12 is the required probability.

3 0

2 years ago

A school dance committee is made up of 2 freshman, 4 sophomores, 2 juniors, and 2 seniors.

qaws [65]

Answer:

4 and 6.

Step-by-step explanation:

There are 4 different grades represented, so for the first question, there are 4 ways that the students can sit if they must sit together by grade.

For the second question, there are 3 grades other than senior level, so it starts with 3 ways that the students can be seated. 3 ways x 2 students per way = 6 ways

7 0

2 years ago