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3 years ago

There are 11 counters in a bag.

Mathematics

1 answer:

-Dominant- [34]3 years ago

3 0

Answer:

For a green and a blue P1 = 8/11 * 3/10 = (80 * 33) / 110^2 = .218

For a blue and a green P2 = 3/11 * 8/10 = (30 * 88) / 110^2 = .218

The probabilities are the same

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3x^2+5x+25, when x=3

Vaselesa [24]

[ Answer ]

$\boxed{121}$

[ Explanation ]

$3x^{2}$ + 5x + 25

X = 3

Replace 3 For X

$3*3^{2}$ + (5 * 3) + 25

Solve

5 * 3 = 15

3 * 3 = 9

9 * 9 = 81

Insert Numbers

81 + 15 + 25

= 121

$\boxed{[ \ Eclipsed \ ]}$

8 0

4 years ago

Read 2 more answers

Please help me i give brainliest

bazaltina [42]

Answer:

Step-by-step explanation:

1. 120+21=141

2. 21-3=18

3. 7x-21

4. 20+x

5. 45+4x

6. 40+5c

7. 20+22r+26s

It will be nice if you give me brainliest

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4 0

3 years ago

(-3.6)-45.19-(-27.033)

patriot [66]

-21.757 because it is right

5 0

3 years ago

What is the the slope line through (2, -2) and (9, 3)

earnstyle [38]

Answer:

5/7

Step-by-step explanation:

3-(-2)/ 9-2

5/7 is the slope

7 0

3 years ago

4/5 divided by 1/3 plus 1/5 minus 3/5

r-ruslan [8.4K]

Answer:

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}=-12$

Step-by-step explanation:

Considering the expression

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}$

Solution Steps:

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}$

$\mathrm{Combine\:the\:fractions\:}\frac{1}{5}-\frac{3}{5}:\quad -\frac{2}{5}$

$=\frac{\frac{4}{5}}{\frac{1}{3}-\frac{2}{5}}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{\frac{b}{c}}{a}=\frac{b}{c\:\cdot \:a}$

$=\frac{4}{5\left(\frac{1}{3}-\frac{2}{5}\right)}$

join $\frac{1}{3}-\frac{2}{5}:\quad -\frac{1}{15}$

$=\frac{4}{5\left(-\frac{1}{15}\right)}$

$\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a$

$=\frac{4}{-5\cdot \frac{1}{15}}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{-b}=-\frac{a}{b}$

$=-\frac{4}{5\cdot \frac{1}{15}}$

$\mathrm{Multiply\:}5\cdot \frac{1}{15}\::\quad \frac{1}{3}$

$=-\frac{4}{\frac{1}{3}}$

$\mathrm{Simplify}\:\frac{4}{\frac{1}{3}}:\quad \frac{12}{1}$

$=-\frac{12}{1}$

$\mathrm{Apply\:rule}\:\frac{a}{1}=a$

$=-12$

Therefore

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}=-12$

4 0

3 years ago