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Mumz [18]
3 years ago
12

Is 7.787878— a rational number?

Mathematics
1 answer:
Vladimir79 [104]3 years ago
5 0

Answer:

yes it is a rational number.

Step-by-step explanation:

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What's the answer to this question= 4(3x + 2) + 2(x + 3)
Serga [27]

Answer:

\huge{ \boxed{ \bold{ \tt{14x + 14}}}}

Option E is the best choice.

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

☯ Question : Simplify

  • 4 ( 3x + 2 ) + 2 ( x + 3 )

☯ Available options :

☐ 12x + 16

☐ 24x + 48

☐ 10x + 2

☐ 14x + 48

☑ 14x + 14

☐ 9x + 5

✎ Step - by - step explanation :

  • \sf{4(3x + 2) + 2(x  + 3)}

Distribute 4 through the parentheses

\dashrightarrow{ \sf{12x + 8 + 2(x + 3)}}

Distribute 2 through the parentheses

\dashrightarrow{ \sf{12x + 8 + 2x + 6}}

Combine like terms. Only coefficients of like terms can be added or subtracted

\dashrightarrow{ \sf{12x + 2x + 8 + 6}}

\dashrightarrow{ \sf{14x + 8 + 6}}

Add the numbers : 8 and 6

\dashrightarrow{ \boxed{ \sf{14x + 14}}}

Hope I helped!

Have a wonderful time ツ

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

6 0
3 years ago
2. Find the number of cubical
lys-0071 [83]

Answer:number of boxes = 60

Volume of box = side × side × side.

 = 3 × 3 × 3

= 27 cu. cm.

Volume of carton = length × breadth × height.

= 15 × 9 × 12

= 1620 cu. cm.

Number of boxes = Volume of carton/Volume of each box.

= 1620/27

= 60

Therefore, number of boxes = 60.

Step-by-step explanation:Volume of box = side × side × side.

 = 3 × 3 × 3

= 27 cu. cm.

Volume of carton = length × breadth × height.

= 15 × 9 × 12

= 1620 cu. cm.

Number of boxes = Volume of carton/Volume of each box.

= 1620/27

= 60

Therefore, number of boxes = 60.

3 0
3 years ago
Pls help me find the value of x
lions [1.4K]

Answer:

x = 3

Step-by-step explanation:

2x+6=x+9 subtract x in both sides

x +6 =9 subtract 6 in both sides

x = 3

4 0
3 years ago
Round 4,204 to the nearest hundred​
Hoochie [10]

Answer:

4200

hope helpful <3 !!!!!!!!!!!!!

8 0
3 years ago
Mary has two job offers.
galina1969 [7]

Answer:

8h+100

8.50h+80

Step-by-step explanation:

7 0
3 years ago
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