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jarptica [38.1K]
2 years ago
12

Pls someone help me or i’ll faint

Mathematics
2 answers:
jekas [21]2 years ago
8 0

Answer:

see explanation

Step-by-step explanation:

Using Pythagoras' identity in the right triangles.

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is

DF² = DE² + EF² , then

(a)

DF² = 16² + 12² = 256 + 144 = 400 ( take square root of both sides )

DF = \sqrt{400} = 20

(b)

DF² = 7² + 2² = 49 + 4 = 53 ( take square root of both sides )

DF = \sqrt{53} ≈ 7.28 ( to 2 dec. places )

never [62]2 years ago
5 0
Answer:
a) DF = 20

b) DF =
Radical Form = sqrt(53)
Decimal Form = 7.28
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Dennis decided he wanted to go to the carnival. The carnival charges $6.00 for entry and $1.50 for each ride.
myrzilka [38]

We want to create a linear equation to model the given situation.

A) c(r) = $6.00 + $1.50*r

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We know that the carnival charges $6.00 for entry plus $1.50 for each ride.

A) With the given information we can see that if you ride for r rides, then the cost equation will be:

c(r) = $6.00 + $1.50*r

Where c(r) is the cost for going to the carnival and doing r rides.

B) If you have $35.00, then we can solve:

c(r) = $35.00 =  $6.00 + $1.50*r

Now we can solve the equation for r.

$35.00 =  $6.00 + $1.50*r

$35.00 -  $6.00 = $1.50*r

$29.00 = $1.50*r

$29.00/$1.50 = r = 19.33

Rounding to the next whole number we get: r = 19

This means that with $35.00, Dennis could go to 19 rides.

If you want to learn more, you can read:

brainly.com/question/13738061

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2 years ago
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Nonamiya [84]

Answer:

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Answer:

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