Pls someone help me or i’ll faint
2 answers:
Answer:
see explanation
Step-by-step explanation:
Using Pythagoras' identity in the right triangles.
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is
DF² = DE² + EF² , then
(a)
DF² = 16² + 12² = 256 + 144 = 400 ( take square root of both sides )
DF = = 20
(b)
DF² = 7² + 2² = 49 + 4 = 53 ( take square root of both sides )
DF = ≈ 7.28 ( to 2 dec. places )
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Easy peasy
if you had
y is inversely proportioal as x that means
y=k/x wher k is a constant
q is invesely peorportionto the square of t
q=k/(t^2)
t=5, q=9.6
easy peasy
subsiute and find k
9.6=k/(5^2)
9.6=k/25
mutiplyb oths ides by 25
240=k
the equation is
q=240/(t^2)
when t=8 then
q=240/(8^2)
q=240/64
q=3.75
q=2.4 find t
2.4=240/(t^2)
multiply both sides by t^2
2.4t^2=240
divide both sides by 2.4
t^2=100
square root both sides
t=10
a. q=
b. q=3.75
c. t=10
if you had
y is inversely proportioal as x that means
y=k/x wher k is a constant
q is invesely peorportionto the square of t
q=k/(t^2)
t=5, q=9.6
easy peasy
subsiute and find k
9.6=k/(5^2)
9.6=k/25
mutiplyb oths ides by 25
240=k
the equation is
q=240/(t^2)
when t=8 then
q=240/(8^2)
q=240/64
q=3.75
q=2.4 find t
2.4=240/(t^2)
multiply both sides by t^2
2.4t^2=240
divide both sides by 2.4
t^2=100
square root both sides
t=10
a. q=
b. q=3.75
c. t=10