Answer: (x+10) to the seccond power
Step-by-step explanation: 1
Use the sum-product pattern
x^{2}+{\color{#c92786}{20x}}+100
x^{2}+{\color{#c92786}{10x}}+{\color{#c92786}{10x}}+100
2
Common factor from the two pairs
x^{2}+10x+10x+100
x(x+10)+10(x+10)
3
Rewrite in factored form
x(x+10)+10(x+10)
(x+10)(x+10)
4
Combine to a square
Answer:
357 mi²
Step-by-step explanation:
The shape is made of a triangle and a half-square
we will calculate the area of each one
let A1 be the area of the half-circle:
A1= (10²*π)/2 = 50π mi²
Let A2 be the area of the triangle:
A2= 10*20=200 mi²
let At be the total area:
At =A1+A2= 200+50π =357.07≈ 357 mi²
<u>Understanding:</u>
This can be easily solved by using the distance formula which is
distance
coordinates of the first point, in our case it is 
coordinates of the second point, 
<u>Solution:</u>
<u></u>![d=\sqrt{[(4)-(1)]^{2}+[(-1)-(-5)]^2}\\=\sqrt{(3)^2+(4)^2}\\= \sqrt{9+16} \\=\sqrt{25}\\= 5](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%5B%284%29-%281%29%5D%5E%7B2%7D%2B%5B%28-1%29-%28-5%29%5D%5E2%7D%5C%5C%3D%5Csqrt%7B%283%29%5E2%2B%284%29%5E2%7D%5C%5C%3D%20%20%5Csqrt%7B9%2B16%7D%20%5C%5C%3D%5Csqrt%7B25%7D%5C%5C%3D%205)
<u></u>
The distance between the two points is 5.
If it’s a regular quadrilateral and c is a right angle then c will be 90 degrees
First error is that the legs are a and b so a should be x and b is 6 and c is 10 the second error is at the end they did not take the square root to get x by itself the real answer should be
X^2 +6^2=10^2
X^2+36=100
X^2 =64
X=8
