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3 years ago

Find the area of the figure to the nearest square unit.

Mathematics

1 answer:

alex41 [277]3 years ago

4 0

Answer:

357 mi²

Step-by-step explanation:

The shape is made of a triangle and a half-square

we will calculate the area of each one

The half square:

let A1 be the area of the half-circle:

A1= (10²*π)/2 = 50π mi²

The rectangle:

Let A2 be the area of the triangle:

A2= 10*20=200 mi²

The whole shape:

let At be the total area:

At =A1+A2= 200+50π =357.07≈ 357 mi²

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Steve sold 36 fruit baskets for a school fundraiser. Evie sold 25% of the number of baskets that Steve sold. How many fruit bask

xeze [42]

Answer:

9 fruit baskets.

Step-by-step explanation:

Given:

Steve sold 36 fruit baskets for a school fundraiser.

Evie sold 25% of the number of baskets that Steve sold.

Question asked:

How many fruit baskets did Evie sell?

Solution:

As given that Evie sold 25% of the number of baskets that Steve sold.

Number of baskets sold by Evie = 25% of 36

$=\frac{25}{100}\times36\\\\ =\frac{900}{100}\\ \\=9$

Thus, 9 fruit baskets sold by Evie.

4 0

3 years ago

If the mean of five values is 8.6 and four of the values are 10, 7, 8, and 7, find

Anna007 [38]

Answer:

The fifth value is 11

6 0

3 years ago

You throw a ball up and its height h can be tracked using the equation h=2x^2-12x+20.

postnew [5]

This problem seems to be wrong because no minimum point was found and no point of landing exists

Answer:

1) There is no maximum height

2) The ball will never land

Step-by-step explanation:

Derivatives

Sometimes we need to find the maximum or minimum value of a function in a given interval. The derivative is a very handy tool for this task. We only have to compute the first derivative f' and have it equal to 0. That will give us the critical points.

Then, compute the second derivative f'' and evaluate the critical points in there. The criteria establish that

If f''(a) is positive, then x=a is a minimum

If f''(a) is negative, then x=a is a maximum

The function provided in the question is

$h(x)=2x^2-12x+20$

Let's find the first derivative

$h'(x)=4x-12$

solving h'=0:

$4x-12=0$

x=3

Computing h''

h''(x)=4

It means that no matter the value of x, the second derivative is always positive, so x=3 is a minimum. The function doesn't have a local maximum or the ball will never reach a maximum height

To find when will the ball land, we set h=0

$2x^2-12x+20=0$