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svlad2 [7]
2 years ago
15

In how many ways can first, second, and third prizes be awarded in a contest with 590 contestants?

Mathematics
1 answer:
Oksanka [162]2 years ago
5 0

Answer:

204,335,880 way's

Step-by-step explanation:

590 ways for the 1 st contestant

589 ways for the 1 st contestant

588ways for the 1 st contestant

590×589×588

204,335,880 way's

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Simplify (5.1)(5.12)4.<br><br> (5.1)6<br> (5.1)7<br> (5.1)8<br> (5.1)9
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The simplified expression of (5.1)(5.1^2)^4 is (5.1)^9

<h3>How to simplify the expression?</h3>

The expression is given as:

(5.1)(5.12)4

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(5.1)(5.1^2)^4

Rewrite the expression properly as follows:

(5.1)(5.1^2)^4 = (5.1) * (5.1^2)^4

Apply the power law of indices

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(5.1)(5.1^2)^4 = (5.1)^9

Hence, the simplified expression of (5.1)(5.1^2)^4 is (5.1)^9

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