Answer:
first and third and fifth
Step-by-step explanation:
big brain time
"In Grade 2 and early in Grade 3, students learned to use bar models to solve two-step problems involving addition and subtraction. This is extended in this chapter to include multiplication and division.
<span>Both multiplication and division are based on the concept of equal groups, or the part-part-whole concept, where each equal group is one part of the whole. In Grade 2, students showed this with one long bar (the whole) divided up into equal-sized parts, or units. This unitary bar model represents situations such as basket of apples being grouped equally into bags." </span>https://www.sophia.org/tutorials/math-in-focus-chapter-9-bar-modeling-with-multipli
The answer is 6 and 1/15.
I think you either need to double 35 or use a protractor. Hope this is helpful!
Answer: In-center of the triangle is point N.
Step-by-step explanation:
We are given a triangle △JKL.
In triangle △JKL, they drew perpendicular bisectors of each side of the triangle.
Also we are given angle bisectors of the each of angles in given triangle.
Note: Perpendicular bisector is a line that intersect a segment into two equal parts and also perpendicular to it.
<em>Also note that the in-center is the point forming the origin of a circle inscribed inside the triangle. It is constructed by taking the intersection of the angle bisectors of the three vertices of the triangle.</em>
<h3>We can see that angle bisectors are intersecting at a point N. </h3><h3>
Therefore, in-center of the triangle is point N.</h3>
