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3 years ago

12p < 96 A. p < 8 B. p < 108 C. p < 84 D. p > –8

Mathematics

2 answers:

Lerok [7]3 years ago

8 0

Given :

12p < 96

Dividing both sides by 12:

12p < 96

$→ \frac{12p}{12}< \frac{96}{12}$

$→ p < 8$

Correct option is A

inessss [21]3 years ago

3 0

Solution:

Note that:

Given inequality: 12p < 96

Dividing both sides by 12:

12p < 96
=> 12p/12 < 96/12
=> p < 8

Correct option is A.

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Approximately how many times greater is 6 x 10^-5 than 5 x 10^-9

8_murik_8 [283]

Answer: $6 \times 10^{-5}$ is $1.2 \times 10^4.$ times greater than $5 \times 10^{-9}$ .

Step-by-step explanation:

We are given two numbers.

First number : $6 \times 10^{-5}$ .

Second number : $5 \times 10^{-9}$ .

In order to find how many times $6 \times 10^{-5}$ is greater than $5 \times 10^{-9}$ , we need to divide first number by second number.

Therefore,

$6 \times 10^{-5}$ ÷ $5 \times 10^{-9}$

or $\frac{6 \times 10^{-5}}{5 \times 10^{-9}}$

First we would divide 6 by 5.

On dividing 6 by 5, we get 1.2.

Now, we would divide 10^-5 by 10^-9.

In order to divide them, we can apply quotient rule of exponents $\frac{a^m}{a^n} =a^{m-n}$ .

We get

$\frac{10^{-5}}{10^{-9}} = 10^{-5-(-9)} = 10^{-5+9} = 10^4$ .

Therefore,

$\frac{6 \times 10^{-5}}{5 \times 10^{-9}}$ = $1.2 \times 10^4.$

So, we could say finally $6 \times 10^{-5}$ is $1.2 \times 10^4.$ times greater than $5 \times 10^{-9}$ .

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3 years ago

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Combine like terms

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