Answer:
1. (x + 5)(x +10)
2. (x - 7)( x - 8)
3. (x - 4)( x - 7)
4. 2(7x−1)(x−9)
5. (2x+9)(x+6)
6. (x−1)(x−2)
7. (2x+3)(x+8)
8. (9x−2)(x−7)
9. 6(x−6)(x+7)
10. (9x+10)(x−4)
11. (3x+7)(x+3)
12. (x−9)(x−9)
13. 4(9x−10)(x−8)
14. 3(x+3)(x−9)
15. 2(x−1)(x+3)
16. 2(3x−1)(x+2)
17. 5(x−2)(x−2)
18. 2(x−1)(x−2)
Step-by-step explanation:
I'm so sorry it took this long that made my brain hurt it was worth it
Sorry it took so long..
hope I helped!!
Taking the derivative of 7 times secant of x^3:
We take out 7 as a constant focus on secant (x^3)
To take the derivative, we use the chain rule, taking the derivative of the inside, bringing it out, and then the derivative of the original function. For example:
The derivative of x^3 is 3x^2, and the derivative of secant is tan(x) and sec(x).
Knowing this: secant (x^3) becomes tan(x^3) * sec(x^3) * 3x^2. We transform tan(x^3) into sin(x^3)/cos(x^3) since tan(x) = sin(x)/cos(x). Then secant(x^3) becomes 1/cos(x^3) since the secant is the reciprocal of the cosine.
We then multiply everything together to simplify:
sin(x^3) * 3x^2/ cos(x^3) * cos(x^3) becomes
3x^2 * sin(x^3)/(cos(x^3))^2
and multiplying the constant 7 from the beginning:
7 * 3x^2 = 21x^2, so...
our derivative is 21x^2 * sin(x^3)/(cos(x^3))^2
Answer:
When the base is less than 1 it's Decay
When the base is greater than 1 it's Growth
