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2 years ago

WILL CHOOSE BRAINLIEST

Mathematics

1 answer:

algol [13]2 years ago

4 0

Answer:

This is the answer if any problem just ask me

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se necesita llenar un galon de agua,en 2 litros se tarda 30 minutos.cuantos litros me hacen falta para completar el galon y cual

mariarad [96]

Answer: 1.78 L are needed to complete the gallon and it will take 29.66 min to completely fill it

Step-by-step explanation:

The question in english is:

A gallon of water needs to be filled, in 2 liters it takes 30 minutes. How many liters do I need to complete the gallon and what is the time it takes me to fill it?

We know 1 gallon is equal to 3.78 liters:

$1 gal=3.78 L$

In addition, we are told you have filled the gallon with $2 L$ at a rate of $\frac{2 L}{30 min}=0.06 L/min$ .

So, if we want to know how many liters are left to completely fill the gallon, we have to sbstract the $2 L$ to the total amount of a gallon:

$3.78 L-2 L=1.78 L$ This is the amount you need to complete the gallon

On the other hand, the rate is defined as:

$rate=\frac{Liters}{time}$

Isolating $time$ :

$time=\frac{Liters}{rate}$

Then, if we input the $1.78 L$ we need to fill the gallon we will have the time:

$time=\frac{1.78 L}{0.06 L/min}$

$time=29.66 min$ This is the time you need to fill the gallon

6 0

3 years ago

lim x rightarrow 0 1 - cos ( x2 ) / 1 - cosx The limit has to be evaluated without using l'Hospital'sRule.

zaharov [31]

Answer with Step-by-step explanation:

Given

$f(x)=\frac{1-cos(2x)}{1-cos(x)}\\\\\lim_{x \rightarrow 0}f(x)=\lim_{x\rightarrow 0}(\frac{1-(cos^2{x}-sin^2{x})}{1-cos(x)})\\\\(\because cos(2x)=cos^2x-sin^2x)\\\\\lim_{x \rightarrow 0}f(x)=\lim_{x\rightarrow 0}(\frac{1-cos^2x}{1-cos(x)}+\frac{sin^2x}{1-cosx})\\\\=\lim_{x\rightarrow 0}(\frac{(1-cosx)(1+cosx)}{1-cosx}+\frac{sin^2x}{1-cosx})\\\\=\lim_{x\rightarrow 0}((1+cosx)+\frac{sin^2x}{1-cosx})\\\\\therefore \lim_{x \rightarrow 0}f(x)=1$

6 0

3 years ago

Can somebody help me with this problem

snow_tiger [21]

it can be useful to represent the entire data set with a single value that describes the "middle" or "average" value of the entire set. In statistics, that single value is called the central tendency and mean, median and mode are all ways to describe it

I hope this helps!!

3 0

3 years ago

Read 2 more answers

Help please !!!!!!!!!!!!

zhenek [66]

I'm pretty sure it is 20 hundreths

8 0

3 years ago

How do you have factor y=6x²+24x-192 and find the zeros?

zvonat [6]

$y=6x^2+24x-192\\\\y=0\ \ \ \Leftrightarrow\ \ \ 6x^2+24x-192=0\ /:6\\\\x^2+4x-27=0\\\\x^2+2\cdot2\cdot x+2^2-2^2-27=0\\\\(x+2)^2-31=0\\\\(x+2)^2=31\ \ \ \Leftrightarrow\ \ \ (x+2= \sqrt{31} \ \ \ or\ \ \ x+2=- \sqrt{31})\\\\x=-2+ \sqrt{31}\ \ \ or\ \ \ x=-2- \sqrt{31}$

3 0

3 years ago